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gtnhenbr [62]
3 years ago
15

The air in an inflated balloon (defined as the system) is warmed over a toaster and absorbs 130 J of heat. As it expands, it doe

s 79 kJ of work. What is the change in internal energy for the system? Express the energy in kilojoules to two significant figures.
Physics
1 answer:
Nadya [2.5K]3 years ago
8 0

Answer:

The change in internal energy for the system = - 78.87 KJ = - 79 KJ to 2 s.f

Explanation:

The first law of thermodynamics states that energy can neither be created nor destroyed but can only be transformed from one form to another.

It goes further to explain that change in the internal energy of a system (ΔU) is the sum of heat exchanged (Q) and the work done (W) by the system or on the system.

If work is done by the system, sign of work is ‘-’, if work is done on the system, the sign of work is ‘+’.

If heat is released by the system, the sign of q is ‘-’. And if heat is gained by the system, then the sign of q is ‘+’.

ΔU = Q + W

Q = 130 J

W = - 79 KJ = - 79000 J

ΔU = 130 - 79000 = - 78870 J = - 78.87 KJ = - 79 KJ

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Answer:

3600joules

Explanation:

formula :W=FS

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S=displacement moved in the direction of force (m)

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Answer:

final velocity = 0

because the train stoped

so,

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3 years ago
Suppose a grower sprays (2.2x10^1) kg of water at 0 °C onto a fruit tree of mass 180 kg. How much heat is released by the water
Bond [772]

There is no temperature change which drives heat flow, thus no heat will be released by the water.

<h3>Heat released by the water when it freezes</h3>

The heat released by the water when it freezes is calculated as follows;

Q = mcΔФ

where;

  • m is mass of water
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Initial temperature of water, Фi = 0 °C

when water freezes, the final temperature, Фf = 0 °C

Q = 22 x 4200 x (0 - 0)

Q = 0

Since there is no temperature change which drives heat flow, thus no heat will be released by the water.

Learn more about heat flow here: brainly.com/question/14437874

6 0
2 years ago
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The beat frequency is the concept required to develop this process. The phenomenon is generated when you have two waves but their frequencies do not differ greatly. So the beat frequency will be the difference between those two waves. For this case we have the difference and one of the waves, therefore,

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Our values are given as,

F_b = 5Hz

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Using the formula of the frequency I will have,

F_b = |F_1-F_2|

Replacing we have,

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F_2 = 1050 \pm 5

F_2 = 1045,1055 Hz

The possible values are two: 1045Hz and 1055Hz

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