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4 years ago

What is the maximum number of unpaired d electrons that an atom or ion can possess?

Physics

1 answer:

Sonbull [250]4 years ago

3 0

Answer:

Explanation:

The d subshell has 5 orbitals, each capable of holding a maximum of two electrons. Hund's rule tells us that every orbital in a sub-level must first be singly occupied by electrons before any orbital is doubly occupied. Therefore five electrons will fill the five orbitals within the d subshell.

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A conducting sphere has a net charge of -4.8x10-17 C. What is the approximate number of excess electrons on the sphere?

Aloiza [94]

Answer:

The number is $N = 300$

Explanation:

From the question we are told that

The net charge is $Q = -4.8 *10^{-17 } \ C$

Generally the charge on a electron is $e = - 1.60 *10^{-19 } \ C$

Generally the number of excess electrons is mathematically represented as

$N = \frac{Q}{e}$

=> $N = \frac{-4.8 *10^{-17}}{-1.60 *10^{-19}}$

=> $N = 300$

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3 years ago

Why can’t we see microwaves

motikmotik

Answer:

The human retina can only detect incident light that falls in waves 400 to 720 nanometers long, so we can't see microwave or ultraviolet wavelengths. This also applies to infrared lights which has wavelengths longer than visible and shorter than microwaves, thus being invisible to the human eye.

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3 years ago

A velocity vs time graph what is the acceleration of the object

tigry1 [53]

Answer:

If the object is moving with an acceleration of +4 m/s/s (i.e., changing its velocity by 4 m/s per second), then the slope of the line will be +4 m/s/s.

Explanation:

7 0

3 years ago

Read 2 more answers

What is the magnitude of electrical force of attraction between an copper nucleus (29 protons) and its innermost electron if the

Agata [3.3K]

The charge of the copper nucleus is 29 times the charge of one proton:
$Q=29 q= 29 \cdot 1.6 \cdot 10^{-19}C=4.64 \cdot 10^{-18}C$
the charge of the electron is
$e=-1.6 \cdot 10^{-19}C$
and their separation is
$r=1.0 \cdot 10^{-12} m$

The magnitude of the electrostatic force between them is given by:
$F=k_e \frac{Qe}{r^2}$
where $k_e$ is the Coulomb's constant. If we substitute the numbers, we find (we can ignore the negative sign of the electron charge, since we are interested only in the magnitude of the force)
$F=(8.99 \cdot 10^9 Nm^2C^{-2}) \frac{(4.64 \cdot 10^{-18}C)(1.6 \cdot 10^{-19}C)}{(1.0 \cdot 10^{-12} m)^2}=6.68 \cdot 10^{-3} N$

3 0

3 years ago

I need help!!! 60 POINTS!!!!

Scrat [10]

Correct one is b
Good luck

3 0

3 years ago

Read 2 more answers