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Nuetrik [128]
2 years ago
5

QUESTION 1: Using the experimental data, calculate the standard reduction potential for each metal, and organise them into a sta

ndard reduction table. Assume E° for B is 0V.
QUESTION 2: Deduce which two metals would produce the highest cell potential in a galvanic cell. Give reasons for your conclusion.

Chemistry
1 answer:
suter [353]2 years ago
6 0

Answer:you should search on google

Explanation:

because its useful

You might be interested in
Which element has two valence electrons?
Colt1911 [192]

Answer:

It is A) Calcium

Explanation:

Calcium has an electronic configuration of 2,8,8,2

6 0
2 years ago
Read 2 more answers
At a certain temperature this reaction follows first-order kinetics with a rate constant of 2.01 s^−1
ddd [48]

Answer:

0.80 seconds (2 significant figures)

Explanation:

The equation of the reaction is given as;

CICH2CH2Cl (g) --> CH2CHCI (g) + HCl(g)

Rate constant (k) = 2.01 s^-1

From the units of the rate constant, this is a first order reaction.

Initial Concentration = 1.34 M

t = ?

Final concentration = 20% of 1.34 = 0.268 M

The integrated rate law for a first order reaction is given as;

ln[A] = ln[A]o - kt

ln(0.268) = ln(1.34) - 2.01(t)

-2.01(t) = - 1.6094

t = 0.8007 ≈ 0.80 seconds (2 significant figures)

6 0
2 years ago
Propenoic acid, C3H4O2, is a reactive organic liquid that is used in the manufacturing of plastics, coatings, and adhesives. An
Shkiper50 [21]

Answer:

C = 39%

H = 5.43%

Explanation:

Firstly, we calculate the number of moles of each.

For carbon, we use carbon iv oxide

Mass here = 0.636g

Number of moles of carbon iv oxide = mass of carbon iv oxide ÷ molar mass of carbon iv oxide. Molar mass = 44g/mol

Number of moles = 0.636 ÷ 44 = 0.014mole

Since 1 mole of carbon iv oxide contains 1 mole carbon, 0.014 mole of carbon iv oxide is also produced.

Mass of carbon = 0.014 × 12 = 0.173g, where 12 is the a.m.u of carbon.

For hydrogen, we use water .

Mass of water = 0.220g

No of moles of water = 0.22 ÷ 18 = 0.012 mole

1 mole of water has two moles of hydrogen, thus the amount of hydrogen produced = 0.012 × 2 = 0.024mole

Mass of hydrogen produced = 0.024 × 1 = 0.024g

The percentage composition are as follows:

Carbon = 0.173/0.442 × 100 = 39%

Hydrogen = 0.024/0.442 × 100 = 5.43%

5 0
3 years ago
An unknown compound contains only carbon and hydrogen. Combustion analysis of the compound produces 0.2845 g of carbon dioxide a
Len [333]

Answer:

C2H5

Explanation:

As the question says, the carbon from the compound is used to form carbon dioxide and the hydrogen is used to form the water, if the analysis of the compound produces 0.2845 g of and 0.1451 g and we know the molar mass of CO2 and H2O(44 and 18 (g/mol), respectively), it is possible to calculate the number of moles of CO2 and H2O.

<u>Number of moles= g/molar mass </u>

Number of moles of CO2= 0.2845g/ (44 g/mol)= 0.0065 moles of CO2, if one mole of CO2 has 1 mole of C, so <em>there are 0.0065 moles of C  </em>

Number of moles of H2O= 0.1451/(18 g/mol)= 0.0081 moles of H2O. There are two hydrogens for each water, so there are 0.0162.

<em>The empirical formula shows the ratio of the elements in the compound</em>, so it is possible to know the ratio between C and H dividing each number of moles by the smallest numer

C= 0.0065/0.0065=1

H=0.0162/0.0065=2.5

Then if we multiply by two, the empirical formula is C2H5, it is because it can´t be represented by non integer numbers.

5 0
3 years ago
Help :L
jok3333 [9.3K]

Answer:

1.6 g/cm3

Explanation:

The formula for Density is actually D=m/v

m= 12.9g

v= 8 cm3

D= \frac{12.9}{8} =1.6125

The unit is grams per centimeters cubed or g/cm3

(If you use the formula given in the question it would be D=0.62)

5 0
3 years ago
Read 2 more answers
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