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Shkiper50 [21]
2 years ago
8

Hello! help me please and thanks

Chemistry
1 answer:
lakkis [162]2 years ago
3 0

Answer:

well I don't know

Explanation:

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Match the term with its description.
Yuliya22 [10]

Photosynthesis is The process that uses sunlight energy to convert water, and carbon dioxide into high energy glucose, and oxygen.




Chloroplast is This organelle of a cell, is where chlorophyll is found. The organelle most involved in photosynthesis.








Hope that helps!!! :)



Chlorophyll is a green pigment present in all plants, that absorbs light to provide energy for photosynthesis.




Energy is the ability to do work, That can produce physical changes within living, and non-living systems.

7 0
3 years ago
 For each phenotype, write the possible genotypes.
Citrus2011 [14]

Answer:

Tall, Res, Dom

short, RES, RES

3 0
3 years ago
A standard solution contained 0.8 mg/mL. A student took 2 mL of the standard solution and added 10 mL of water. What is the new/
galben [10]
To get the concentration of the second solution let us use the following formulae

C1V1=C2V2 where C1 is concentration of first solution and V1 is the volume of solution first solution. on the other hand C2 is the concentration of second solution and V2 is the volume of second solution.

therefore

0.8×2=(2+10)×C2
   1.6 =12×C2
1.6/12=C2
C2     = 0.1333mg/mL
7 0
3 years ago
Read 2 more answers
Hvgiyhhhhhhhhhhh fvytufyutfjhfytudcthjhhh
skad [1K]

Answer:

ndudbndidneeejebdbsuwinsbdhdbendisjwnwhiwjendbdjdjrndnidj

Explanation:

geheurjd dnienendjenenjenendndnsjjsj

8 0
2 years ago
7.26 of a hydrate, Cu(NO3)2.xH2O, formed 2.4 g copper(II) oxide.
goldfiish [28.3K]

Number of moles= mass/ molar mass

Or n=m/MM

n = number of moles

m = mass

MM = molar mass

1) n CuO = 2.4g / 79.54g/mol = 0.03 mol CuO

2) n Cu(NO3)2.xH2O = 7.26 g / 205.6 = 0.035 moles of Cu(NO3)2.xH2O

3) 205.6 g

Cu = 63.5 g

N = 14g

O =16g

H= 1 g

63.5+ (14+(16*3))*2+1*2+16 =205.6 g

4) yes is 188g

5) I don’t know, I assume was 1

6 0
3 years ago
Read 2 more answers
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