Question

the distance of the earth to the sun is 1.5x10^11 m and one year is 365days if the distance to the sun increased six time the initial value how long it take the earth to orbit the sun?

Answer 1

Answer:

x = 2190[days]

Explanation:

This problem can be solved by means of a simple three rule:

$1.5*10^{11}=365[days]\\ 6*(1.5*10^{11})=x\\\\x= \frac{6*(1.5*10^{11})*365[days]}{1.5*10^{11}} \\x=2190[days]$