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Bingel [31]
3 years ago
15

Someone help me, I'm stuck

Physics
1 answer:
Bas_tet [7]3 years ago
3 0
C is the answer hope that helps you
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What is statement can most likey be useing in the shock waves of atmoic bomb
Neko [114]

Answer:

The initial energy emission occurs by 80% or more in the form of gamma rays but these are quickly absorbed and dispersed mostly by air in little more than a microsecond, converting gamma radiation into thermal radiation (thermal pulse ) and kinetic energy (shock wave) which are actually the two dominant effects in the initial moments of the explosion. The rest of the energy is released in the form of delayed radiation (fallout or fallout) and is not always counted when measuring the performance of the explosion.

Explanation:

High altitude explosions produce greater damage and extreme radiation flux due to lower air density (photons encounter less opposition) and consequently a higher blast wave is generated.

8 0
3 years ago
A car traveling on a straight road at 10 meters per second accelerates uniformly to a speed of 21 meters per second in 12 second
labwork [276]
21+10=31 because you can see that 21 and 10 are in metres while 12 is in seconds so 21+10=31 is the answer.
6 0
3 years ago
A 7.5 kg block is placed on a table. if it's bottom surface area is 0.6m2, how much pressure does the block exert on the tableto
xeze [42]
The answer to this is B.
3 0
3 years ago
Fiora starts riding her bike at 20 mi/h. after a while, she slows down to 12 mi/h, and maintains that speed for the rest of the
hammer [34]
<span>d = r*t

t = hours at 20 mi/hr


20t + 12*(4.5 - t) = 70
8t = 16
t = 2 hours

d at 20 mi/hr = 20*2 = 40 miles

40/20 + 30/12 = 4.5 hours

Fiora travels a total distance of 4.5 hours</span>
3 0
3 years ago
Read 2 more answers
The specific heat of fat is roughly 1,700 J/(kgoC) whereas that for water is around 4200 J/(kgoC). A 0.63 kg solution of lipids
BartSMP [9]

Answer:

the mass of the lipid content, to the nearest hundredth of a kg, in this solution =0.46 kg

Explanation:

Total heat content of the fat = heat content of water +heat content of the lipids

Let it be Q

the Q= (mcΔT)_lipids + (mcΔT)_water

total mass of fat  M= 0.63 Kg

Q= heat supplied = 100 W in 5 minutes

ΔT= 20°C

c_lipid= 1700J/(kgoC)

c_water= 4200J/(kgoC)

then,

100\times5\times60= m(1700)20+(0.63-m)(4200)20

solving the above equation we get

m= 0.46 kg

the mass of the lipid content, to the nearest hundredth of a kg, in this solution =0.46 kg

3 0
3 years ago
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