Answer b protons and electrons
Answer:
The law of conservation of mass or principle of mass conservation
Explanation:
It states that for any system closed to all transfers of matter and energy, the mass of the system must remain constant over time, as the system's mass cannot change, so quantity can neither be added nor be removed.
Answer:
i. The error is the rough convex mirror.
ii. This should be replaced with a smooth convex morror.
Explanation:
Reflection is dependent on the surface involved and has two types; diffuse and specular. When the surface is rough, diffused reflection is observed. The surface causes a distortion of the incident light (the rays would be reflected at different angles to one another) after reflection. This makes some rays to interfere with one another. While specular reflection is observed with a smooth surface.
In the statement, the rough convex mirror would produce a distorted reflection which would produce diffused reflection. The effect is that few or no rays (depending on the degree of how rough the surfce is) would be reflected to the other smooth, flat diagonal mirror.
Answer:
A los 10 segundos su velocidad será 15 
Explanation:
La aceleración de un objeto es una magnitud que indica cómo cambia la velocidad del objeto en una unidad de tiempo.
En otras palabras, la aceleración relaciona los cambios de la velocidad con el tiempo en el que se producen, es decir que mide cómo de rápidos son los cambios de velocidad:
- Una aceleración grande significa que la velocidad cambia rápidamente.
- Una aceleración pequeña significa que la velocidad cambia lentamente.
- Una aceleración cero significa que la velocidad no cambia.
La aceleración "a" puede ser calculada mediante la expresión:
En este caso:
- a= 1
- vfinal= ?
- vinicial= 5
- tiempo= 10 s
Reemplazando:
Resolviendo se obtiene:
1 *10 s= vfinal - 5
10 = vfinal - 5
10 + 5 = vfinal
15 = vfinal
<u><em>A los 10 segundos su velocidad será 15 </em></u><u><em></em></u>
Answer:
1. -8.20 m/s²
2. 73.4 m
3. 19.4 m
Explanation:
1. Apply Newton's second law to the car in the y direction.
∑F = ma
N − mg = 0
N = mg
Apply Newton's second law to the car in the x direction.
∑F = ma
-F = ma
-Nμ = ma
-mgμ = ma
a = -gμ
Given μ = 0.837:
a = -(9.8 m/s²) (0.837)
a = -8.20 m/s²
2. Given:
v₀ = 34.7 m/s
v = 0 m/s
a = -8.20 m/s²
Find: Δx
v² = v₀² + 2aΔx
(0 m/s)² = (34.7 m/s)² + 2 (-8.20 m/s²) Δx
Δx = 73.4 m
3. Since your braking distance is the same as the car in front of you, the minimum safe following distance is the distance you travel during your reaction time.
d = v₀t
d = (34.7 m/s) (0.56 s)
d = 19.4 m
