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e-lub [12.9K]
3 years ago
5

Copper has a specific heat of 0.09 cal/g x C . How much change in temperature would the addition of 8373 cal of heat have on a 5

38.0 gram sample of copper
Physics
1 answer:
neonofarm [45]3 years ago
3 0
<h3>Answer:</h3>

172.92 °C

<h3>Explanation:</h3>

Concept being tested: Quantity of heat

We are given;

  • Specific heat capacity of copper as 0.09 cal/g°C
  • Quantity of heat is 8373 calories
  • Mass of copper sample as 538.0 g

We are required to calculate the change in temperature.

  • In this case we need to know that the amount of heat absorbed or gained by a substance is given by the product of mass, specific heat capacity and change in temperature.
  • That is, Q = m × c × ΔT

Therefore, to calculate the change in temperature, ΔT we rearrange the formula;

ΔT = Q ÷ mc

Thus;

ΔT = 8373 cal ÷ (538 g × 0.09 cal/g°C)

    = 172.92 °C

Therefore, the change in temperature will be 172.92 °C

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The arrow was moving at 15.9 m/s.

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An electron is released from rest at the negative plate of a parallel plate capacitor and accelerates to the positive plate (see
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(7.90 × 10⁻¹⁵) J

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F = ma

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a = (4.646 × 10⁻¹³)/(9.11 × 10⁻³¹)

a = (5.10 × 10¹⁷) m/s²

Now, using the equations of motion, we can obtain the velocity with which the electron reaches the positive plate

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Hope this Helps!!!

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