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Yuliya22 [10]
3 years ago
6

A wave is incident on the surface of a mirror at an angle of 41° with the normal. what can you say about its angle of reflection

?
Physics
2 answers:
galina1969 [7]3 years ago
8 0

Answer:

<h2> the answer is<u><em> B .</em></u></h2><h3><u><em>#PLATOFORLIFE </em></u></h3>

Umnica [9.8K]3 years ago
7 0

It's angle of reflection must be 41 degrees

we know, by the first law of reflection that angle of incidence is always equal to angle of reflection..........

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Does the uphill or downhill direction matter to the speed of the marble, or is the height the only contributing variable?
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B down hill is the fastest
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A hover craft also known as a air cushion vehicle glides on a cushion of air allowing it to travel with equal is land or water.
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Answer: M = 1797.75 kg

Explanation:

given parameters are;

speed V = 26.7 M/S.

momentum P = 4.8×10^4 KGM/S.

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Momentum P is the product of mass and velocity. That is, P = MV

Substitute V and P into the formula

4.8×10^4 = 26.7 × M

Make M the subject of formula

M = 4.8×10^4/ 26.7

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4 0
2 years ago
Question 20 of 20
Sphinxa [80]

Answer:

a

Explanation:

hI I

6 0
1 year ago
Cheetahs, the fastest of the great cats, can reach 50.0 miles/hour in 2.22 s starting from rest. Assuming that they have constan
elena55 [62]

Answer:

10.07m/s^2

Explanation:

Information we have:

velocities:

initial velocity: v_{i}=0mph (starts from rest)

final velocity: v_{f}=50mph

time:  t=2.22s

Since we need the answer in m/s^2, we nees to convert the speed to meters per second:

v_{f}=\frac{50miles}{1hour}(\frac{1hour}{3,600s} )(\frac{1609.34meters}{1mile} ) \\\\v_{f}=\frac{50*1609.34}{3600} m/s\\\\v_{f}=22.35m/s

We find the acceleration with the following formula:

a=\frac{v_{f}-v_{i}}{t}

substituting the known values:

a=\frac{22.35m/s-0m/s}{2.22s}\\ \\a=10.07m/s^2

the acceleration is 10.07m/s^2

8 0
2 years ago
Read 2 more answers
A ship sets sail from Rotterdam, The Netherlands, intending to head due north at 6.5 m/s relative to the water. However, the loc
sattari [20]

Answer:

Explanation:

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velocity of water with respect to earth = 1.5 m/s at 40° north of east

\overrightarrow{v}_{w,e}=1.5\left ( Cos40\widehat{i} +Sin40\widehat{j}\right)

velocity of ship with respect to water = velocity of ship with respect to earth - velocity of water with respect to earth

\overrightarrow{v}_{s,w} = \overrightarrow{v}_{s,e} - \overrightarrow{v}_{w,e}

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\overrightarrow{v}_{s,e} = - 1.15 \widehat{i}+5.54\widehat{j}

The magnitude of the velocity of ship relative to earth is \sqrt{1.15^{2}+5.54^{2}} = 5.66 m/s

5 0
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