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larisa86 [58]
3 years ago
9

The reaction ag+(aq) + cl−(aq) ↔ agcl(s) has an equilibrium of 1020 (keq = 1020). if you have a beaker containing 1 liter of wat

er with 0.1 mol of agcl(s) in it along with 10−6 m ag+(aq) and 10−15 m cl−(aq), how does the reaction shift?
Chemistry
1 answer:
lord [1]3 years ago
3 0
When Q is equal the initial concentration of the products / the initial concentration of the reactants. 

so, Q = [Ag]*[Cl-]  and we neglected [AgCl] as it is solid

∴ Q = 10^-6 * 10^-5 

       = 10^-11 

now we will compare the value of Q with the value of Keq:

when Q = Keq so, the system is in equilibrium

and when Q > Keq so, the reaction will go forward (shift to right) to achieve equilibrium.

and when Q< Keq so, the reaction will go left (shift to left) to achieve equilibrium.

when Q = 10^-11 and Keq = 10^20

∴Q< Keq 

and the reaction will shift to left.
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Answer:

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Explanation:

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The process of cytokinesis is different for animal cell and plant cell.

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Hence, from the given information of the question,

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xenn [34]
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sergey [27]

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Now that we have moles we use the relative formula mass of NaCO₃, We have 1 Na atom, 1 C atom and 3 O atoms, thus

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5 0
3 years ago
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mel-nik [20]

Answer:

Tile 52 and three are incorrect

Explanation:

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