ANSWER ASAP PLEASE

1 answer:

3 0

Density is equal to mass divided by volume so the densest object will be the object that has the largest mass in the smallest area. In this case object A is the densest with a density of 10g/cm^3. I hope this helps. Let me know if anything is unclear.

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Reacts with air..physical or chemical property ;)

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It is a chemical process - an oxidation.

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Which groups on the periodic table contain metalloids?

Firlakuza [10]

Groups 13-16, hope this helps!

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Consider the following element combinations. Classify the bonds formed between each pair as ionic, polar covalent, or nonpolar c

Sati [7]

An ionic bond is formed by the transfer of electrons from one atom to the other. It is usually formed between a metal + non-metal.

A covalent bond is formed by sharing of electrons between two atoms. It is formed between two nonmetals. A polar covalent bond is formed between 2 non-metals which differ in their electronegativities. In contrast, in a non-polar covalent interaction the two atoms could either be the same or have very close electronegativities.

1) P and I : Both non-metals with different electronegativities= Polar Covalent

2) Fe and O: Metal + non-metal = Ionic

3) S and Cl: Both non-metals with different electronegativities= Polar Covalent

4) S and S: Both non-metals and the same atoms = Non-polar Covalent

5) Br and Br: Both non-metals and the same atoms = Non-polar Covalent

6) O and Cl: Both non-metals with different electronegativities= Polar Covalent

7) Be and Cl: Metal + non-metal = Ionic

8) Al and N: Metal + non-metal = Ionic

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3 years ago

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Which phrase best discribes wave motion

kap26 [50]

Answer:

propagation of disturbances—that is, deviations from a state of rest or equilibrium—from place to place in a regular and organized way. Most familiar are surface waves on water, but both sound and light travel as wavelike disturbances, and the motion of all subatomic particles exhibits wavelike properties.

Explanation:

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4 years ago

N2+3H2---> 2NH3

irakobra [83]

Hello!

A) How many grams of hydrogen are necessary to react completely with 50.0g of nitrogen in the above reaction?

The balanced chemical reaction is the following one:

N₂(g) + 3H₂(g) → 2NH₃(g)

To calculate the amount of hydrogen necessary we will use the following conversion factor to go from grams of nitrogen to grams of hydrogen:

$50 gN_2* \frac{1 mol N_2}{28,013 g N_2}* \frac{3 moles H_2}{1 mol N_2}* \frac{2,016 g H_2}{1 mol H_2}=10,7950 g H_2$

So, 10,7950 grams of H₂ are required to react with 50 g of nitrogen

B) How many grams of ammonia are produced in the reaction from the previous problem?

The balanced chemical reaction again is the following one:

N₂ + 3H₂ → 2NH₃

To calculate the amount of ammonia produced we will use the following conversion factor to go from grams of nitrogen to grams of ammonia:

$50 gN_2* \frac{1 mol N_2}{28,013 g N_2}* \frac{2 moles NH_3}{1 mol N_2}* \frac{17,031 g NH_3}{1 mol NH_3}=60,7968 g NH_3$

So, 60,7968 grams of NH₃ are produced from 50 g of nitrogen

C) How many grams of silver chloride are produced from 5.0g of silver nitrate reacting with an excess of barium chloride?

The balanced chemical equation for the reaction is the following one:

2AgNO₃ + BaCl₂ → 2AgCl + Ba(NO₃)₂

To calculate the mass of Silver Chloride produced we will use the following conversion factor to go from grams of Silver Nitrate to grams of Silver Chloride:

$5 g AgNO_3* \frac{1 mol AgNO_3}{169,87 g AgNO_3}* \frac{2 moles AgCl}{2 moles AgNO_3}* \frac{143,32 g AgCl}{1 mol AgCl}=4,2185 g AgCl$

So, 4,219 g of AgCl are produced from the reaction of 5 g of AgNO₃

D) How much barium chloride is necessary to react with the silver nitrate in the previous problem?

The balanced chemical equation for the reaction is the following one:

2AgNO₃ + BaCl₂ → 2AgCl + Ba(NO₃)₂

To calculate the mass of Barium Chloride necessary we will use the following conversion factor to go from grams of Silver Nitrate to grams of Barium Chloride:

$5 g AgNO_3* \frac{1 mol AgNO_3}{169,87 g AgNO_3}* \frac{1 mol BaCl_2}{2 moles AgNO_3}* \frac{208,23 g BaCl_2}{1 mol BaCl_2}=3,08 g BaCl_2$

So, 3,08 g of BaCl₂ are produced from the reaction of 5 g of AgNO₃

Have a nice day!

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3 years ago