Answer:
L = 8694 Kg.m²/s
Explanation:
r = 270 ĵ m
v = 14 î m/s
m = 2.3 kg
θ = 90º
L = ?
We can apply the equation
L = m*v*r*Sin θ
L = (2.3 kg)*(14 m/s)*(270 m)*Sin 90º = 8694 Kg.m²/s
Therefore, the magnitude of magnetic field at a distance 1.10cm from the origin is 27.3mT
<u>Explanation:</u>
Given;
Number of turns, N = 1000
Inner radius, r₁ = 1cm
Outer radius, r₂ = 2cm
Current, I = 1.5A
Magnetic field strength, B = ?
The magnetic field inside a tightly wound toroid is given by B = μ₀ NI / 2πr
where,
a < r < b and a and b are the inner and outer radii of the toroid.
The magnetic field of toroid is

Substituting the values in the formula:


Therefore, the magnitude of magnetic field at a distance 1.10cm from the origin is 27.3mT
Avg acceleration; under constant acceleration condition only; = Vf-Vi/time
a=Vf-Vi/time=(15m/s-6m/s)/(3s)=
(9m/s)/(3s)=3m/s^2
Hope this helps. Thanks.
<span>♥B. There was no single medium of exchange.♥
Take a look at the saying </span><span>"Not worth a Continental".
It referrers to the fact that </span><span>currency issued by the Continental Congress was usually just a promise to pay.
Leaving your answer with ♥B♥</span>
Answer:

Explanation:
The question says that, "The closest star to the earth is 2 light years away. Calculate this distance in SI units".
Given that,
The distance between the closest star and the Earth is 2 light years.
The SI unit of distance is m. It means we need to convert light years to meters. We know that,

2 light-years means,

So, the required distance is equal to
.