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Vlada [557]
3 years ago
5

there are 60 fish in the pond. use your experimental probability to predict how many are pink salmon, yellowfin tuna and blue gi

ll
Mathematics
1 answer:
Talja [164]3 years ago
5 0

Answer: I got it right on the tutorial

Step-by-step explanation:

Pink salmon: 25

Yellowfin Tuna: 0

Bluegill: 25

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You are a business owner and you want to know if you have made a profit
Gennadij [26K]

Answer: Yes the business made a profit for the month. They made $90,000 net profit. They made a profit of $90,000 after all the taxes were deducted.

Step-by-step explanation: 200 times $1000 = $200,000. $200,000 - $50,000 = $150,000. $150,000 - $40,000 = $110,000. $110,000 - $20,000 = $90,000

7 0
3 years ago
What is (+5) - (-1) - (-3)
maksim [4K]
+ = positive
Positive and positive makes a positive

Negative and negative makes a positive

- = negative
Negative and positive makes a negative

Positive and negative makes a negative

Your answer: +5 - (-1) = 6
+6 - (-3) = +9
Your answer that youre looking for is: 9


4 0
3 years ago
ryan takes a 30 centimeter by 72 centimeter sheet of paper and cuts from one corner of the paper to diagonally opposite corner.
nikklg [1K]

Answer:

178

Step-by-step explanation:

Use Pythagorean Theorem to find the Hypotenuse

30^2+72^2=78^2

Use perimeter formula

a+b+c

38+72+30

3 0
3 years ago
Read 2 more answers
I’ll give brainliest to whoever can do this
tino4ka555 [31]

i forgot hiw to do that

Step-by-step explanation:

8 0
3 years ago
Find all of the equilibrium solutions. Enter your answer as a list of ordered pairs (R,W), where R is the number of rabbits and
zloy xaker [14]

Answer:

(0,0)   (4000,0) and (500,79)

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the equilibrium solutions

We have:

\frac{dR}{dt} = 0.09R(1 - 0.00025R) - 0.001RW

\frac{dW}{dt} = -0.02W + 0.00004RW

To solve this, we first equate \frac{dR}{dt} and \frac{dW}{dt} to 0.

So, we have:

0.09R(1 - 0.00025R) - 0.001RW = 0

-0.02W + 0.00004RW = 0

Factor out R in 0.09R(1 - 0.00025R) - 0.001RW = 0

R(0.09(1 - 0.00025R) - 0.001W) = 0

Split

R = 0   or 0.09(1 - 0.00025R) - 0.001W = 0

R = 0   or  0.09 - 2.25 * 10^{-5}R - 0.001W = 0

Factor out W in -0.02W + 0.00004RW = 0

W(-0.02 + 0.00004R) = 0

Split

W = 0 or -0.02 + 0.00004R = 0

Solve for R

-0.02 + 0.00004R = 0

0.00004R = 0.02

Make R the subject

R = \frac{0.02}{0.00004}

R = 500

When R = 500, we have:

0.09 - 2.25 * 10^{-5}R - 0.001W = 0

0.09 -2.25 * 10^{-5} * 500 - 0.001W = 0

0.09 -0.01125 - 0.001W = 0

0.07875 - 0.001W = 0

Collect like terms

- 0.001W = -0.07875

Solve for W

W = \frac{-0.07875}{ - 0.001}

W = 78.75

W \approx 79

(R,W) \to (500,79)

When W = 0, we have:

0.09 - 2.25 * 10^{-5}R - 0.001W = 0

0.09 - 2.25 * 10^{-5}R - 0.001*0 = 0

0.09 - 2.25 * 10^{-5}R = 0

Collect like terms

- 2.25 * 10^{-5}R = -0.09

Solve for R

R = \frac{-0.09}{- 2.25 * 10^{-5}}

R = 4000

So, we have:

(R,W) \to (4000,0)

When R =0, we have:

-0.02W + 0.00004RW = 0

-0.02W + 0.00004W*0 = 0

-0.02W + 0 = 0

-0.02W = 0

W=0

So, we have:

(R,W) \to (0,0)

Hence, the points of equilibrium are:

(0,0)   (4000,0) and (500,79)

4 0
3 years ago
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