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nikklg [1K]
2 years ago
13

Identify a conjugate acid-base pair in the reaction

Chemistry
2 answers:
timurjin [86]2 years ago
5 0

Answer: it’s A

Explanation:

Just took the test

Marta_Voda [28]2 years ago
4 0

Answer:

The correct answer is option A.

Explanation:

According to the Bronsted-Lowry conjugate acid-base theory:

An acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

For the given chemical equation:

NH_3+H_2O\rightleftharpoons NH_4^{+}+OH^-

Here, H_2O is loosing a proton, thus it is considered as an acid and after losing a proton, it forms OH^- which is a conjugate base.

And, NH_3 is gaining a proton, thus it is considered as a base and after gaining a proton, it forms NH_4^{+} which is a conjugate acid.

Hence, the correct answer is option A.

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pochemuha
   The energy change  if 84.0 g   of CaO  react  with  excess  water is  98KJ of heat is released.

calculation
heat  =  number of moles  x  delta H

delta H = - 65.2  Kj/mol

first find the number of  moles  of  CaO reacted

moles = mass/molar mass
the molar mass  of CaO =  40 +  16=  56 g/mol
mass = 84 g
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Heat is therefore =  1.5 moles  x -65.2 = - 97.8 Kj = -98 Kj

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3 years ago
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melamori03 [73]

Answer:

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Explanation:

Step 1: Calculate the heat required to heat the water.

We use the following expression.

Q = c \times m \times \Delta T

where,

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The average density of water is 1 g/mL, so 75.0 mL ≅ 75.0 g.

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Step 2: Calculate the heat released by the methane

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\frac{-22.0kJ}{64.00g} \times \frac{16.04g}{mol} = -5.51 kJ/mol

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