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nikklg [1K]
3 years ago
13

Identify a conjugate acid-base pair in the reaction

Chemistry
2 answers:
timurjin [86]3 years ago
5 0

Answer: it’s A

Explanation:

Just took the test

Marta_Voda [28]3 years ago
4 0

Answer:

The correct answer is option A.

Explanation:

According to the Bronsted-Lowry conjugate acid-base theory:

An acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

For the given chemical equation:

NH_3+H_2O\rightleftharpoons NH_4^{+}+OH^-

Here, H_2O is loosing a proton, thus it is considered as an acid and after losing a proton, it forms OH^- which is a conjugate base.

And, NH_3 is gaining a proton, thus it is considered as a base and after gaining a proton, it forms NH_4^{+} which is a conjugate acid.

Hence, the correct answer is option A.

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How many molecules (not moles) of NH3 are produced from 5.25x10^-4 g of H2?
Oksi-84 [34.3K]

Answer:

not 100% but i think its 1.57x10^20

Explanation:

5.25x10^-4g / 2.016g

2.60x10^-4 x 6.022x10^23= 1.56x10^20 molecules

6 0
3 years ago
What kind of energy is required for photosynthesis to occur​
Makovka662 [10]

Answer:

light energy to convert carbon dioxide and water into glucose and oxygen gas. Each molecule of glucose essentially “stores” up to 38 molecules of ATP which can be broken down and used during other cellular reactions.

Explanation:

6 0
3 years ago
Read 2 more answers
HELP PLSS!
Inessa05 [86]
. The empirical formula is the simplest whole number ratio.

The correct answer is 1. HCI
7 0
2 years ago
During a lab, you heat 1.62 g of a CoCl2 hydrate over a Bunsen burner. After heating, the final mass of the dehydrated compound
sashaice [31]
Answer is: formula of hydrate is CoCl₂· 6H₂O -c<span>obalt(II) chloride hexahydrate
</span>m(CoCl₂· xH₂O) = 1,62 g.
m(CoCl₂) = 0,88 g.
n(CoCl₂) = m(CoCl₂) ÷ M(CoCl₂)
n(CoCl₂) = 0,88 g ÷ 130 g/mol
n(CoCl₂) = 0,0068 mol.
m(H₂O) = 1,62 g - 0,88 g.
m(H₂O) = 0,74 g.
n(H₂O) = m(H₂O) ÷ m(H₂O) 
n(H₂O) = 0,74 g ÷ 18 g/mol
n(H₂O) = 0,041 mol.
n(CoCl₂) : n(H₂O) = 0,0068 mol : 0,041 mol.
n(CoCl₂) : n(H₂O) = 1 : 6.
8 0
3 years ago
You are given 10ml (M) 20 Naoh solution in a conical flask and asked to titrate with (M) 20 Hcl and (M) 20 H2so4 separately. cal
Solnce55 [7]

Answer:

n_{HCl}=0.2molHCl\\n_{H_2SO_4}=0.1molH_2SO_4

Explanation:

Hello!

In this case, since the reactions between NaOH and the acids are:

NaOH+HCl\rightarrow NaCl+H_2O\\\\2NaOH+H_2SO_4\rightarrow Na_2SO_4+2H_2O

Whereas we can see the 1:1 and 2:1 mole ratios between NaOH and HCl and H2SO4 respectively. In such a way, at the equivalence point we realize that:

n_{HCl}=n_{NaOH}=V_{NaOH}M_{NaOH}=0.01L*20mol/L=0.2molHCl\\\\2n_{H_2SO_4}=n_{NaOH}\\\\n_{H_2SO_4}=\frac{1}{2} V_{NaOH}M_{NaOH}=\frac{0.01L*20mol/L}{2} =0.1molH_2SO_4

Best regards!

8 0
3 years ago
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