This graph compares the amounts of three different substances that can dissolve in 100 g of water at temperatures between 0° C a
nd 100° C.
Which substance is most soluble?
substance 1
substance 2
substance 3
Which substance is most soluble?
substance 1
substance 2
substance 3
2 answers:
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Answer:
The heat of the reaction is 105.308 kJ/mol.
Explanation:
Let the heat released during reaction be q.
Heat gained by water: Q
Mass of water ,m= 1kg = 1000 g
Heat capacity of water ,c= 4.184 J/g°C
Change in temperature = ΔT = 26.061°C - 25.000°C=1.061 °C
Q=mcΔT
Heat gained by bomb calorimeter =Q'
Heat capacity of bomb calorimeter ,C= 4.643 J/g°C
Change in temperature = ΔT'= ΔT= 26.061°C - 25.000°C=1.061 °C
Q'=CΔT'=CΔT
Total heat released during reaction is equal to total heat gained by water and bomb calorimeter.
q= -(Q+Q')
q = -mcΔT - CΔT=-ΔT(mc+C)
Moles of propane =
0.0422 moles of propane on reaction with oxygen releases 4.444 kJ of heat.
The heat of the reaction will be:
Answer:
Explanation:
Here, we want to convert J to cal
Mathematically:
Thus, to get our answer in cal, we divide the value given by 4.186
We have that as: