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QveST [7]
3 years ago
14

This graph compares the amounts of three different substances that can dissolve in 100 g of water at temperatures between 0° C a

nd 100° C.
Which substance is most soluble?


substance 1


substance 2


substance 3

Chemistry
2 answers:
oksian1 [2.3K]3 years ago
3 0
Substance 2 I think sorry if I’m wrong
bearhunter [10]3 years ago
3 0
I also think it’s substance 2
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In a neutral atom, the number of protons is always equal to what other part of the atom?
Licemer1 [7]

Answer:

b. The number of electrons

Explanation:

A "neutral atom" has a <u>neutral charge</u>. This means that <em>its charge is equal to </em><em>zero. </em>In order for the charges to cancel out each other, the atom's <em>positive charge should be equal to the negative charge. </em>These being said, the number of electrons<em> (negatively-charged)</em> is then equal to the number of protons <em>(positively-charged). </em>Those atoms which are not neutral are called <em>"ions."</em> This means that they either have more or less electrons than the protons.

7 0
3 years ago
HELP ASAP PLEASE!!!! 15 PTS!!
Bond [772]
ADD THEM all, and then divide by four. Thats what I would do! 
5 0
3 years ago
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How many atoms in 7.55 mole of Iron atom
vagabundo [1.1K]

7.55 x 6.02 x 10²³ = 4.55 x 10²⁴ atoms

4 0
2 years ago
Iodine-131 decays with a half-life of 8.02
dlinn [17]
Radioactive material undergoes 1st order decay kinetics.

For 1st order decay, half life = 0.693/k

where k = rate constant

k = 0.693/half life = 0.693/8.02 = 0.0864 day-1

Now, for 1st order reaction,
k = \frac{2.303}{t} X log \frac{initial.conc}{final.conc}

Given: t = 6.01d, initial conc. = 5mg

∴0.0864 = \frac{2.303}{6.01} X log \frac{5}{final.conc}
∴ final conc. = 2.975 mg
3 0
3 years ago
When the pH of a solution changes from a pH of 5 to a pH of 3, the hydronium ion concentration is
gizmo_the_mogwai [7]

Answer : The correct option is, (D) 100 times the original content.

Explanation :

As we are given the pH of the solution change. Now we have to calculate the ratio of the hydronium ion concentration at pH = 5 and pH = 3

As we know that,

pH=-\log [H_3O^+]

The hydronium ion concentration at pH = 5.

5=-\log [H_3O^+]

[H_3O^+]=1\times 10^{-5}M      ..............(1)

The hydronium ion concentration at pH = 3.

3=-\log [H_3O^+]

[H_3O^+]=1\times 10^{-3}M      ................(2)

By dividing the equation 1 and 2 we get the ratio of the hydronium ion concentration.

\frac{[H_3O^+]_{original}}{[H_3O^+]_{final}}=\frac{1\times 10^{-5}}{1\times 10^{-3}}=\frac{1}{100}

100\times [H_3O^+]_{original}=[H_3O^+]_{final}

From this we conclude that when the pH of a solution changes from a pH of 5 to a pH of 3, the hydronium ion concentration is 100 times the original content.

Hence, the correct option is, (D) 100 times the original content.

7 0
3 years ago
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