Answer:
Like you, like you
Like you, ooh
I found it hard to find someone like you
Like you, like you
Send your location, come through
I can't sleep no more
In my head, we belong
And I can't be without you
Why can't I find no one like you?
I can't sleep no more
In my head, we belong
And I can't be without you
Why can't I find no one like you?
Explanation:
Answer:
Three hydrogen atoms to form PH₃.
Explanation:
Hello!
In this case, since the elements belonging to the nitrogen family (N, P, As, Sb and Bi) show five valence electrons, because there are five electrons at their outer shell, it is clear that if phosphorous bonds with hydrogen, it is going to require the same amount of oxygen atoms (3) because elements having five valence electrons need 3 bonds in order to attain the octet (5+3=8).
Therefore the compound would be:

Which is phosphine.
Best regards!
Answer:Um... I think 5000 i am not really sure
Explanation: I Dont Really Know
Aluminium Carbonate on Dissociation produces Aluminium Ions and carbonate Ions as follow,
Al₂(CO₃)₃ → 2 Al⁺³ + 3 CO₃⁻²
Result:
On dissociation Al₂(CO₃)₃ produces FIVE Ions in total. The Ions produced and there number are as follow;
Al⁺² = 2
CO₃⁻² = 3
Answer:
0.11%
Explanation:
Without mincing words, let us dive straight into the solution to the question/problem. The first step to solve this question is to write out the chemical reaction, that is the reaction showing the dissociation of acetic acid.
CH3COOH <=======================================> CH3COO⁻ + H⁺
Initially, the amount present in the acetic acid which is = 12M, the concentration for CH3COO⁻ and H⁺ is 0 respectively.
At equilibrium, the amount present in the acetic acid which is = 12 - x, the concentration for CH3COO⁻ = x and H⁺ = x respectively. Note that the ka for acetic acid = 1.8 × 10⁻⁵.
1.8 × 10⁻⁵ = x²/ 14 - x. Therefore, x = 0.0158 M.
The next thing to do is to calculate for the percentage of dissociation, this can be done as given below:
percentage of dissociation = x/14 × 100. Recall that the value that we got for x = 0.0158 M. Hence, the percentage of dissociation = 0.0158 M/ 14m × 100 = 0.11%