The usefulness of mendeleev s periodic table was confirmed by

A sample of 42 mL of carbon dioxide gas was placed in a piston in order to maintain a constant 101 kPa of pressure.

Lilit [14]

Answer:

The answer to your question is 33.4 ml

Explanation:

Data

volume 1 = V1 = 42 ml

temperature 1 = T1 = 20°C

temperature 2 = T2 = -60°C

Volume 2 = V2 = x

Process

1.- Convert celsius to kelvin

T1 = 20 + 273 = 293°K

T2 = -60 + 273 = 233°K

2.- Use the Charles' law to solve this problem

$\frac{V1}{T1} = \frac{V2}{T2}$

Solve for V2

V2 = $\frac{V1T2}{T1}$

3.- Substitution

V2 = $\frac{(42)(233)}{293}$

4.- Simplification

V2 = $\frac{9786}{293}$

5.- Result

V2 = 33.4ml

3 0

3 years ago

The chemical equation below shows the burning of magnesium (Mg) with oxygen (O2) to form magnesium oxide

scoundrel [369]

Answer:

64

Explanation:

B

4 0

3 years ago

How many molecules of co2 are there in 4.56 moles of co2?

Marianna [84]

Answer:

<h3>The answer is 2.75 × 10²⁴ molecules</h3>

Explanation:

The number of molecules of CO2 can be found by using the formula

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 4.56 × 6.02 × 10²³

We have the final answer as

<h3>2.75 × 10²⁴ molecules</h3>

Hope this helps you

4 0

3 years ago

Classify the following as a physical property (phys) or a chemical property (chem). (a) Silver metal has a shiny luster. (b) Sil

ANTONII [103]

Answer:

Explanation:

Hello,

The question above requires us to classify certain properties which may either fall into physical or chemical properties of that matter.

Physical properties are properties which are of intrinsic value and has no influence on the chemical nature of the substance while chemical properties are those that influence the chemical nature of the substance.

Physical properties can be measured or calculated while chemical properties of a substance is very difficult to measure.

a). Silver has a shiny luster is an example of "physical property" because the shiny nature of silver has no chemical importance.

b). Silver metal has a density of 10.49 g/cm³ is also a "physical property" because density is a physical property of a material.

Density is ratio between mass and volume which are both physical properties since they can be measured.

c). Silver metal and Chlorine gas produce Silver chloride (AgCl) is a "chemical property" since it involves combining of two elements and they both lose their original chemical identity after the reaction.

d). Silver metal has a melting point of 1235°C is a "physical property"

e). Silver metal conducts electricity is a "chemical property" since conduction of electricity are done by the availability of mobile electrons in its electron cloud.

f) silver metal gives no reaction to acid is also an example of "chemical property"

7 0

3 years ago

10.00 mL of the final acid solution is reacted with excess barium chloride to produce a precipitate of barium sulfate (Fw: 233.4

Verizon [17]

Answer:- Actual molarity of the original sulfuric acid solution is 17.0M.

Solution:- Barium chloride reacts with sulfuric acid to make a precipitate of barium sulfate. The balanced equation is written as:

$BaCl_2(aq)+H_2SO_4(aq)\rightarrow BaSO_4(s)+2HCl(aq)$

From this equation there is 1:1 mol ratio between barium sulfate and sulfuric acid. So, if excess of barium chloride is added to sulfuric acid then the moles of sulfuric acid would be equivalent to the moles of barium sulfate. Moles of barium sulfate could be calculated from the mass of it's dry precipitate.

Molar mass of barium sulfate is 233.4 grams per mol. The calculations for the moles of sulfuric acid are given below:

$0.397gBaSO_4(\frac{1molBaSO_4}{233.4gBaSO_4})(\frac{1moH_2SO_4}{1molBaSO_4})$

= $0.00170molH_2SO_4$

From given information, 10.00 mL of final acid solution were taken to react with excess of barium chloride. It means 0.00170 moles of sulfuric acid are present in 10.0 mL of final acid solution. We could calculate the actual molarity of the final solution from here as:

10.0 mL = 0.0100 L

$molarity=\frac{0.00170mol}{0.0100L}$

= 0.170M

Now we would use the dilution equation to calculate the actual molarity of the original sulfuric acid solution. The molarity equation is:

$M_1V_1=M_2V_2$

From given information, 10.0 mL of original acid solution were taken in a 100 mL flask and water was added up to the mark. It means the 10 fold dilution is done. 10 fold dilution means the molarity becomes one tenth of it's original value. Let's do the calculations in reverse way as we have calculated the molarity of the final solution.

let's say the molarity after first dilution is Y. the volume is taken as 10.0 mL. Final volume is 100 mL and the molarity is 0.170M. Let's plug in the values in the equation:

Y(10.0mL) = 0.170M(100mL)

$Y=\frac{0.170M*100mL}{10.0mL}Y = 1.70MLet's do the similar calculations to find out the actual molarity of the original acid solution. Let's say the molarity of the original acid solution is X. 10.0 mL of it were taken and diluted to 100 mL on adding water. The molarity is 1.70M as is calculated in the above step. Let's plug in the values in the molarity equation again to solve it for X as:X(10.0mL) = 1.70M(100mL)[tex]X=\frac{1.70M*100mL}{10.0mL}$

X = 17.0M

Hence, the actual molarity of sulfuric acid solution is 17.0M.

5 0

3 years ago