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ValentinkaMS [17]
3 years ago
14

How do you calculate the gravitational force on a rubber ball which has a mass of 50g

Physics
1 answer:
AfilCa [17]3 years ago
6 0
P (gravitational force) = m (mass) x g
<=> P = 0.05 x 10
<=> P = 0.5N
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On a roller coaster, riders can experience a force of up to 4 g. What is the maximum acceleration of the roller coaster?
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m/s^2 is 39.2266

is the answer If thats what you needed


7 0
3 years ago
When the electron in a hydrogen atom moves from n = 6 to n = 1, light with a wavelength of ________ nm is emitted?
Oduvanchick [21]
First we find the energy level with the following formula, where a is the energy level, n1 is the final energy level, n2 is the starting energy level and r is Rydberg's constant in Joules
a = r \times ( \frac{1}{n1}  -  \frac{1}{n2} )
We insert the values

a = 2.18 \times  {10}^{ - 18}  \times ( \frac{1}{ {1}^{2} } -  \frac{1}{ {6}^{2} }  )
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The wavelength is found with this formula, where h is Planck's constant and c is the speed of light
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Finally we insert the values
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3 0
3 years ago
A 25 kg block is held against a compressed spring and then the spring is allowed to decompress giving the block a velocity. The
Alex787 [66]

Answer:

h=18.05 cm

Explanation:

Given that

m= 25 kg

K= 1300 N/m

x=26.4 cm

θ= 19.5 ∘

When the block just leave the spring then the speed of block = v m/s

From energy conservation

\dfrac{1}{2}Kx^2=\dfrac{1}{2}mv^2

Kx^2=mv^2

v=\sqrt{\dfrac{kx^2}{m}}

By putting the values

v=\sqrt{\dfrac{kx^2}{m}}

v=\sqrt{\dfrac{1300\times 0.264^2}{25}}

v=1.9 m/s

When block reach at the maximum height(h) position then the final speed of the block will be zero.

We know that

V_f^2=V_i^2-2gh

By putting the values

0^2=1.9^2-2\times 10\times h

h=0.1805 m

h=18.05 cm

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3 years ago
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Fudgin [204]

Answer:

need points sorry god bless

Explanation:

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3 years ago
Which things determine an element's electronegativity? Check all that apply. A. The size of the atom of that element B. Whether
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D. The number of electrons
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