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Yanka [14]
2 years ago
13

At which points on the roller coaster is the car not moving?

Physics
1 answer:
Scrat [10]2 years ago
3 0

The maximum potential energy of the car or the when car is not moving at points A and E; option A.

<h3>What is potential energy?</h3>

Potential energy is the energy of a body due to its state or position.

In the rollercoaster motion shown, the maximum potential energy occurs when the car is no longer moving.

At different points other than at maximum potential energy, the energy is a combination of potential and kinetic energy.

The maximum potential energy occurs at A and E, at which point the car is not moving.

In conclusion, at maximum potential energy, the car is not moving.

Learn more about potential energy at: brainly.com/question/14427111

#SPJ1

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Waves in the ocean are energy travelling along water.

Waves do not transport mass, they transport energy, this is the ability to perform work or exert force and distant points.

Although water seems to be travelling along with the wave, the molecules of water only move up and down; they do not travel along with the wave.
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A 160cm long string has two adjacent resonance at 85hz frequencies . calculate : 1- the fundamental frequency , 2- the speed of
lara [203]

Length=l=160cm=1.6m

Frequency=85Hz

#1

Fundamental frequency be v

\\ \sf\bull\longmapsto v=\dfrac{\nu}{2\ell}

\\ \sf\bull\longmapsto v=\dfrac{85}{2(1.6)}

\\ \sf\bull\longmapsto v=\dfrac{85}{3.2}

\\ \sf\bull\longmapsto v=26.6Hz

#2

First we have to find wavelength

\\ \sf\bull\longmapsto \lambda=\dfrac{c}{v}

\\ \sf\bull\longmapsto \lambda=\dfrac{3\times 10^8ms^{-1}}{26.6}

\\ \sf\bull\longmapsto \lambda=0.112\times 10^8m

\\ \sf\bull\longmapsto \lambda=112\times 10^5m

\\ \sf\bull\longmapsto \lambda=1.12\times 10^6m

Now..

Velocity be v

\\ \sf\bull\longmapsto v=f\lambda

  • f is frequency

\\ \sf\bull\longmapsto v=26.5\times1.12\times 10^6m

\\ \sf\bull\longmapsto v=29.68\times 10^6

\\ \sf\bull\longmapsto v=2.9\times 10^7m/s

5 0
3 years ago
A wire is stretched between two posts. Another wire is stretched between two posts that are four times as far apart. The tension
Elena-2011 [213]

Answer:

Therefore,

The speed of the wave on the longer wire is 95 m/s.

Explanation:

Given:

For Short wire, speed is

v_{s}=190\ m/s

Let length of Short  and Longer wire be L_{s}\ and\ L_{l} such that

L_{l}=4\times L_{s}

To Find:

v_{l}=?  Speed on the longer wire

Solution:

The speed of a pulse or wave on a string under tension can be found with the equation,

v=\sqrt{\dfrac{F_{T}\times L}{m}

Where,

F_{T} = Tension on the wire

L = Length of Sting

m = mass of String

So here we have,

F_{T} = same

L_{l}=4\times L_{s}

Therefore,

v_{s}=\sqrt{\dfrac{F_{T}\times L_{s}}{m} ......equation ( 1 )

And

v_{l}=\sqrt{\dfrac{F_{T}\times L_{l}}{m}  .......equation ( 2 )

Dividing equation 1 by equation 2 and on Solving we get

\dfrac{v_{s}}{v_{l}}=\sqrt{\dfrac{L_{s}}{L_{l}}}

Therefore,

v_{l}=v_{s}\sqrt{\dfrac{4\times L_{s}}{L_{s}}}=190\times 2=380\ m/s

Therefore,

The speed of the wave on the longer wire is 95 m/s.

8 0
3 years ago
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