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3 years ago

Which of the following is an example of Newton's second law of motion?

Physics

2 answers:

laiz [17]3 years ago

5 0

Answer:

Explanation:

Newton’s Second Law of Motion

Newton’s Second Law of Motion states that ‘when an object is acted on by an outside force, the mass of the object equals the strength of the force times the resulting acceleration’.

This can be demonstrated dropping a rock or and tissue at the same time from a ladder. They fall at an equal rate—their acceleration is constant due to the force of gravity acting on them.

The rock's impact will be a much greater force when it hits the ground, because of its greater mass. If you drop the two objects into a dish of water, you can see how different the force of impact for each object was, based on the splash made in the water by each one.

uysha [10]3 years ago

4 0

Answer: B

Explanation:

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Solve 3.4 = 5.1(3.7x + 4.7) for x.

solniwko [45]

Answer:

Explanation:

3.4 = 18.87x + 23.97

collecting like terms

3.4 - 23.97 = 18.87x

-20.57 = 18.87x

dividing both sides by 18.87

x = -20.57/18.87

x= -1.09

6 0

3 years ago

Read 2 more answers

You want to lift a heavy box with a mass L = 56.0 kg using the two-ideal pulley system as shown. With what minimum force do you

Olin [163]

The minimum force required to lift the box at constant velocity is determined as 274.4 N.

<h3>Minimum force required</h3>

The minimum force required to lift the box at constant velocity is the tension in one of the pulleys, and the magnitude is calculated as follows;

2T = mg

where;

m is mass of the box
T is the minimum force required

2T = mg

T = mg/2

T = (56 x 9.8)/2

T = 274.4 N

Learn more about minimum force here: https://brainly.in/question/47873510

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3 0

2 years ago

QUESTION 4.

n200080 [17]

Answer:

Follows are the solution to this question:

Explanation:

Please find the correct question in the attachment file.

Let:

$\overrightarrow{R}= R_i\hat{i}+R_j\hat{j}+R_k\hat{k}\\\\\overrightarrow{S}= S_i\hat{i}+S_j\hat{j}+S_k\hat{k}\\\\$

Calculating the value of $\overrightarrow{R} \times \overrightarrow{S}:$

$\to \left | \begin{array}{ccc}\hat{i}&\hat{j}&\hat{K}\\R_i&R_j&R_k\\S_i&S_j&S_k\end{array}\right | = \hat{i}[R_j S_k-S_jR_k]-\hat{j}[R_i S_k-S_iR_k]+\hat{k}[R_i S_j-S_iR_j]$

Calculating the value of $\overrightarrow{R} \cdot (\overrightarrow{R} \times \overrightarrow{S}):$

$\to (R_i\hat{i}+R_j\hat{j}+R_k\hat{k}) \cdot ( \hat{i}[R_j S_k-S_jR_k]-\hat{j}[R_i S_k-S_iR_k]+\hat{k}[R_i S_j-S_iR_j])$

by solving this value it is equal to 0.

8 0

2 years ago

A flat, 179 179 ‑turn, current‑carrying loop is immersed in a uniform magnetic field. The area of the loop is 4.41 cm 2 4.41 cm2

Alecsey [184]

Answer:

The value of the magnetic field is $B =0.1423T$

Explanation:

From the question we are told that

The number of turns is $N = 179$

The area of the loop is $A = 4.41cm^2 = \frac{4.41}{10000} = 0.000414m$

The angle is $\theta = 59^o$

The torque is $\tau =2.25 * 10^{- 5} N$

The current is $I = 2.49\ mA$

The torque acting on the current carry loop is mathematically represented as

$\tau = B * I * N * A * sin \theta$

Where is the magnitude of the magnetic filed

Making B the subject

$B= \frac{\tau}{I * N * A * sin\theta}$

Substituting values

$B = \frac{2.25*10^{-5}}{2.49*10^{-3} * 179 * 0.000414 * sin (59)}$

$=0.1423 T$

4 0

3 years ago

A skydiver jumped out of a plane, determine distance he distance he descended after 5 seconds. Gravity is pulling him down at 10

Bond [772]

The distance travelled in 5 seconds is 125 m

Explanation:

The motion of the skydiver is a free fall motion, since he is acted upon the force of gravity only. Therefore, it is a uniformly accelerated motion, with constant acceleration downward, and we can find the distance he travels by using the following suvat equation:

$s=ut+\frac{1}{2}at^2$