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4 years ago

Which of the following is an example of Newton's second law of motion?

Physics

2 answers:

laiz [17]4 years ago

5 0

Answer:

Explanation:

Newton’s Second Law of Motion

Newton’s Second Law of Motion states that ‘when an object is acted on by an outside force, the mass of the object equals the strength of the force times the resulting acceleration’.

This can be demonstrated dropping a rock or and tissue at the same time from a ladder. They fall at an equal rate—their acceleration is constant due to the force of gravity acting on them.

The rock's impact will be a much greater force when it hits the ground, because of its greater mass. If you drop the two objects into a dish of water, you can see how different the force of impact for each object was, based on the splash made in the water by each one.

uysha [10]4 years ago

4 0

Answer: B

Explanation:

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Does a stone lying on the ground have stored energy

Vesnalui [34]

Yes, It has a stored energy in that stone.

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3 years ago

You look at a barometer and see that the air pressure is getting much higher... How will the weather probably change? *

Murljashka [212]

Answer:

The weather will clear up and get sunnier.

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3 years ago

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List the levels of classification in order from most broad (largest number of organisms) to most specific (smallest number of or

Tju [1.3M]

Every organism may classified into seven level of classifications, such that each level contains organisms with similar characteristics. Kingdom is the largest and the broadest level of classification while species is the smallest and most specific level of classification. Therefore from the largest to the smallest the order is as follows:
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4 years ago

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The pressure gauge shown below has a spring for which k = 60 N/m, and the area of the piston is 0.50 cm2. Its right end is conne

kicyunya [14]

Answer:

0.025 m

0.059166 m

Explanation:

P = Pressure

A = Area

x = Compression of spring

Force is given by

$F=PA\\\Rightarrow F=30000\times 0.5\times 10^{-4}\\\Rightarrow F=1.5\ N$

From Hooke's law

$F=kx\\\Rightarrow x=\dfrac{F}{k}\\\Rightarrow x=\dfrac{1.5}{60}\\\Rightarrow x=0.025\ m$

The spring is compressed 0.025 m

In the second case

$F_1=1.5\ N$

$F_2=101000\times 0.5\times 10^{-4}\\\Rightarrow F_2=5.05\ N$

Net force would be

$F=F_2-F_1\\\Rightarrow F=5.05-1.5\\\Rightarrow F=3.55\ N$

Compression would be

$x=\dfrac{F}{k}\\\Rightarrow x=\dfrac{3.55}{60}\\\Rightarrow x=0.059167\ m$

The compression of the spring is 0.059166 m

8 0

3 years ago

While two forces act on it, a particle of mass m=3.2kg is it to move continuously with velocity (3m/s)i - (4m/s)j . one of the f

marta [7]

Mmm tricky.
Since the velocity is constant, I'm going to assume there is no acceleration in any direction. This means there is no net force in the I or J forection!

Since there are 2 forces, both must be equal and opposite in direction to perfectly cancel each other out.

So the opposite of F1 is (-2N)I + (6N)J!

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4 years ago