Answer:
The wavelength of the waves on the string is found using v = λf:
λ = v/f = 315/370 = 0.85135m
The first harmonic (fundamental) standing wave formed on the string has nodes only at the ends (see diagram in link) so:
String length = λ/2 = 0.85135/2 = 0.426m (to 3 sig. figs.)
That's false. If it had only magnitude it would be speed. Velocity also has Direction.
2(5) + 2 (z) = 10{3}
10 + 2z= 30
2z=20
z=10
Answer:
The radius of the sphere is 4.05 m
Explanation:
Given;
potential at surface,
= 450 V
potential at radial distance,
= 150
radial distance, l = 8.1 m
Apply Coulomb's law of electrostatic force;
![V = \frac{KQ}{r} \\\\V_s = \frac{KQ}{r} \\\\V_r = \frac{KQ}{r+ l}](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7BKQ%7D%7Br%7D%20%5C%5C%5C%5CV_s%20%3D%20%5Cfrac%7BKQ%7D%7Br%7D%20%5C%5C%5C%5CV_r%20%3D%20%5Cfrac%7BKQ%7D%7Br%2B%20l%7D)
![450 = \frac{KQ}{r} ------equation (i)\\\\150 = \frac{KQ}{r+8.1} ------equation (ii)\\\\divide \ equation (i)\ by \ equation \ (ii)\\\\\frac{450}{150} = (\frac{KQ}{r} )*(\frac{r+8.1}{KQ} )\\\\3 = \frac{r+8.1}{r} \\\\3r = r + 8.1\\\\2r = 8.1\\\\r = \frac{8.1}{2} \\\\r = 4.05 \ m](https://tex.z-dn.net/?f=450%20%3D%20%5Cfrac%7BKQ%7D%7Br%7D%20------equation%20%28i%29%5C%5C%5C%5C150%20%3D%20%5Cfrac%7BKQ%7D%7Br%2B8.1%7D%20------equation%20%28ii%29%5C%5C%5C%5Cdivide%20%5C%20equation%20%28i%29%5C%20by%20%5C%20equation%20%5C%20%28ii%29%5C%5C%5C%5C%5Cfrac%7B450%7D%7B150%7D%20%3D%20%28%5Cfrac%7BKQ%7D%7Br%7D%20%29%2A%28%5Cfrac%7Br%2B8.1%7D%7BKQ%7D%20%29%5C%5C%5C%5C3%20%3D%20%5Cfrac%7Br%2B8.1%7D%7Br%7D%20%20%5C%5C%5C%5C3r%20%3D%20r%20%2B%208.1%5C%5C%5C%5C2r%20%3D%208.1%5C%5C%5C%5Cr%20%3D%20%5Cfrac%7B8.1%7D%7B2%7D%20%5C%5C%5C%5Cr%20%3D%204.05%20%5C%20m)
Therefore, the radius of the sphere is 4.05 m
Solid iron at 25°C
the cooler the temperature the less energy the particles have