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matrenka [14]
2 years ago
14

laser with wavelength 633 nm illuminates a single slit of width 0.185 mm. The diffraction pattern is seen on a screen. The dista

nce between the first and second dark fringes is 8.25 mm. How far is the screen from the slit
Physics
1 answer:
soldier1979 [14.2K]2 years ago
5 0
A helium-neon laser (λ = 633 nm) illuminates a single slit and is observed on a screen 1.30 m behind the slit. The distance between the first and second minima in the diffraction pattern is 3.95 mm .
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The synthesis of nitrogen trihydride from nitrogen gas and hydrogen gas is shown by which balanced chemical equation?
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8 0
3 years ago
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A woman flies 300 kilometers north, 200 kilometers west, and 500 kilometers south. How far is she from her starting point?
maria [59]
She is
\sqrt{200^2+200^2}=  ~282.84 kilometers away from her starting point
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3 years ago
What are the characteristics of a blackbody radiator? Give an example.
mihalych1998 [28]

Answer:

A blackbody, or Planckian radiator, is a cavity within a heated material from which heat cannot escape. No matter what the material, the walls of the cavity exhibit a characteristic spectral emission, which is a function of its temperature.

Example:

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3 0
2 years ago
Question 1 of 7What is the change in internal energy if 90 J of thermal energy is added to asystem, and the system does 30 J of
Dmitriy789 [7]

Given:

The thermal energy added to the system is Q = 90 J

The work done by the system on the surroundings is W = 30 J

To find the change in internal energy.

Explanation:

According to the first law of thermodynamics, the change in internal energy can be calculated by the formula

\Delta U=\text{ Q-W}

On substituting the values, the change in internal energy will be

\begin{gathered} \Delta U\text{ =90-30} \\ =60\text{ J} \end{gathered}

Final Answer: The chage in internal energy is 60 J (option D)

5 0
10 months ago
When an automobile moves with constant speed down a highway, most of the power developed by the engine is used to compensate for
uysha [10]

Answer:

F=5449 N

Explanation:

Work done is a product of force and displacement ie

Work done, W, = Force*Displacement

Power, P, is Work done/Time

P=\frac {W}{t}=\frac {FS}{t} where P is power, W is work done, F is force, S is displacement and t is time

In this case, F is the frictional force. Converting the power from hp to W, we multiply by 746 hence P=746*168=125328  W

Since displacement/time is velocity, then

P=FV where V is velocity in m/s

Making F the subject

F=\frac {P}{V}

F=\frac {125328}{23}=5449.043478  N

F=5449 N

7 0
3 years ago
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