the answer to the question is false
A. 90km/h = 25 m/s
W=1/2mv^2
=1/2* 650* 25^2
= 203125(J)
b. v’= 90-50= 40km/h
= 100/9 m/s
W=1/2mv^2
=1/2*650*(100/9)^2
= 40123,45679
Answer:633.8 KJ
Explanation:
Given
mass of water
Initial temperature
Final temperature 
Specific heat of water
=4190 J/kg-k
heat of vaporization
Heat required for process
=heat to raise water temperature from 20 to 100 +Heat to vapourize water completely
Q=mc
Q=
Q=
Q=