Solution :
Given :
Mass attached to the spring = 4 kg
Mass dropped = 6 kg
Force constant = 100 N/m
Initial amplitude = 2 m
Therefore,
a).
= 10 m/s
Final velocity, v at equilibrium position, v = 5 m/s
Now,
A' = amplitude = 1.4142 m
b).
m' = 2m
Hence,
c).
Therefore, factor
Thus, the energy will change half times as the result of the collision.
Answer:
<u>Capacitor and the dielectrics:</u>
"The capacitor is a charge,q storing device as it is subjected to the potential difference between the different plates and thus results in the difference of charge decomposition between the two plates."
<u>Formula:</u>C= ∈°(A/d),
<u>Unit:</u> Farad,F.
In order to store or hold the optimum number of charge particles,q between the plates we have a number of insulators which are used as the medium between the two plates.While, it separates both the plates from one another.
Explanation:
<u>Dielectric Constants in the capacitors:</u>
In order to hold the number of charges in between the plates of the capacitor a specific medium or substrate is placed(mostly the insulators). As it covers the area between the two capacitors, while it can decrease and increase by the action of the movable plate of the capacitor.
Now, it increase the capcitative power of the capacitor by decreasing the potential difference between the two plates, along with which the electromagnetic field is also greatly reduced.As the interaction between the two plates is greatly reduced, as they are covered and well protected by the sheet or membrane of insulting medium around them.
