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Ray Of Light [21]
3 years ago
11

Write the Ka expression for an aqueous solution of hydrofluoric acid: (Note that either the numerator or denominator may contain

more than one chemical species. Enter the complete numerator in the top box and the complete denominator in the bottom box. Remember to write the hydronium ion out as , and not as ) Ka
Chemistry
1 answer:
damaskus [11]3 years ago
4 0

Answer:

Ka = ( [H₃O⁺] . [F⁻] ) / [HF]

Explanation:

HF is a weak acid which in water, keeps this equilibrium

HF (aq)  +  H₂O (l)  ⇄  H₃O⁺ (aq)  +  F⁻ (aq)      Ka

2H₂O (l)  ⇄  H₃O⁺ (l)  +  OH⁻ (aq)   Kw

HF is the weak acid

F⁻ is the conjugate stron base

Let's make the expression for K

K = ( [H₃O⁺] . [F⁻] ) / [HF] . [H₂O]

K . [H₂O] = ( [H₃O⁺] . [F⁻] ) / [HF]

K . [H₂O] = Ka

Ka, the acid dissociation constant, includes Kwater.

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jok3333 [9.3K]

Answer:

D. all of these

Explanation:

In the classification of organisms, they are placed into groups which they appropriately fit into.

All the choices given correctly shows the process of classifying organisms. This aspect of biology is described as taxonomy.

  • Based on characteristics of organisms, they are put into the same groups
  • Also, we can identify the related family and genus in which a discovered organism can be put into.
  • They phylogenetic relationship between organisms are important for classification.
7 0
3 years ago
In each equation, label the acids, bases, and conjugate acid-base pairs. (Type your answer using the format [NO3]- for NO3-.)
Kamila [148]

Answer:

a) O²⁻ + H₂O <-----> OH⁻ + OH⁻

Acid = H₂O

Base = O²⁻

Conjugate Acid = OH⁻

Conjugate Base = OH⁻

b) HClO₄ + H₂SO₄ <-----> ClO₄⁻ + H₃SO₄⁺

Acid = HClO₄

Base = H₂SO₄

Conjugate Acid = H₃SO₄⁺

Conjugate Base = ClO₄⁻

c) NH₃ + HNO₃ <--> NH4⁺ + NO₃⁻

Acid = HNO₃

Base = NH₃

Conjugate Acid = NH4⁺

Conjugate Base = NO₃⁻

Explanation:

- Acids are molecules or ions capable of donating a proton (H⁺).

- Bases are molecules or ions that readily accept the H⁺ from acids.

- Conjugate Acids, according to the Brønsted–Lowry acid–base theory, are chemical compounds formed after the reception of a proton (H⁺) from an acid by a base.

- Conjugate Bases, Brønsted–Lowry acid–base theory, are the leftovers from when acids donate their proton (H⁺).

4 0
3 years ago
Consider the balanced chemical reaction when phosphorus and iodine react to produce phosphorus triodide: 2 P(s) + 3 I2(g) → 2 PI
melamori03 [73]

Answer:

Percent yield of PI3 = 95.4%

Explanation:

This is the reaction:

2P (s) + 3I2 (g) > 2PI3 (g)

Let's determine the moles of iodine that has reacted.

58.6 g / 253.8 g/mol = 0.231 mol

Ratio is 3:2. Let's make a rule of three to state the moles produced at 100 % yield reaction.

3 moles of I2 react to make 2 moles of PI3

0.231 moles of I2 would make (0.231 .2) / 3 = 0.154 moles of PI3

As we have produced 0.147 moles let's determine the percent yield.

(Yield produced / Theoretical yield) . 100 > (0.147 / 0.154) . 100 = 95.4%

5 0
3 years ago
A loaf of bread has a green substance growing on each slice. Which of the following types of spoilage could have occurred?
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3 years ago
Automobile air bags inflate following a serious impact. The impact triggers the following chemical reaction.
Rus_ich [418]

Answer:

Explanation:

To determine the molar volume of the gas according to the equation at stp;

1 mole = 22.4 dm³

2 moles = 44.8 dm³

To determine the mass of NaN₃ inflated according to the equation

2NaN₃ (where Na = 23g and N = 14) = (2 × 23) + 2(14 × 3)

= 130 g

Hence, if 130g of NaN₃ is required to inflate 44.8 dm³ airbag upon impact

what mass of NaN₃ is required to fully inflate the air bag upon impact;

130g ⇒ 44.8 dm³

? ⇒ 11.9 dm³ (dm³ is same as L)

? = 130 × 11.9/44.8

? = 34.5g

34.5g of NaN₃ is required to fully inflate 11.9 L of air bag upon impact

3 0
3 years ago
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