Answer:
combustion of methane gass will take place when the flame is yellow
When an electron in a quantum system drops from a higher energy level to a lower one, the system<u> emit a photon.</u>
<u />
The energy of the electron drops when it transitions levels, as well as the atom releases photons. The emission of the photon occurs as the electron transitions from an energy state to a lower state. The photon energy represents precisely the energy that would be lost when an electron moves to a level with less energy.
When such an excited electron transitions from one energy level to another, this could emit a photon. The energy drop would be equivalent to the power of the photon that is released. In electron volts, the energy of an electron, as well as its associated photon (emitted or absorbed) has been stated.
Therefore, when an electron in a quantum system drops from a higher energy level to a lower one, the system<u> emit a photon.</u>
<u />
To know more about electron
brainly.com/question/1255220
#SPJ4
<u />
Mercury naturally exists in Liquid state.
On Condensing it can exist in Solid state as well.
Hope it helps...
Regards;
Leukonov/Olegion.
Molecular Motion<span> is the speed at which molecules or atoms move dependent on temperature and state of matter.
Explanation:
</span>All molecules are<span> in constant motion. Molecules of a liquid have </span>a lot of<span> freedom of movement than those </span>in an exceedingly<span> solid. Molecules </span>in an exceedingly<span> gas have </span>the best<span> degree of motion.</span>
<span>
Heat, temperature </span>and also the<span> motion of molecules </span>area unit<span> all </span>connected<span>. Temperature </span>could be a life<span> of </span>the common K.E.<span> of the molecules </span>in an exceedingly<span> material. Heat </span>is that the<span> energy transferred between materials that have </span>completely different temperatures<span>. Increasing the temperature </span>will increase<span> the </span>travel<span> motion of molecules Energy </span>is expounded<span> to temperature by the relationship.</span>
