The time taken by Carbon-14 to decay radioactively from 120g to 112.5g is 22,920 years.
<h3>How do we calculate the total time of decay?</h3>
Time required for the whole radioactive decay of any substance will be calculated by using the below link:
T = (n)(t), where
- t = half life time = 5730 years
- n = number of half life required for the decay
Initial mass of Carbon-14 = 120g
Final mass of Carbon-14 = 112.5g
Left mass = 120 - 112 = 7.5g
Number of required half life for this will be:
- 1: 120 → 60
- 2: 60 → 30
- 3: 30 → 15
- 4: 15 → 7.5
4 half lives are required, now on putting values we get
T = (4)(5730) = 22,920 years
Hence required time for the decay is 22,920 years.
To know more about radioactive decay, visit the below link:
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Some people naturally have more or less blemishes than others because of genes
Explanation:
hdy hey hey hegzyv vu g g ycgx
Answer: Option (c) is the correct answer.
Explanation:
When current passes through a wire then a magnetic field is formed. Therefore, when two wires carry current in the same direction then both the wires with have respective magnetic fields in the same direction and their total magnetic field will be large.
But when current between two wires flow in opposite direction then the magnetic field produced will also be in opposite direction. Therefore, both the magnetic fields cancel each other out. Thus, total magnetic field will be small.
As a result, wires which carry current in the opposite direction repel each other.
Answer:
The frequency of the photon is 7.41*10¹⁶ Hz
Explanation:
Planck states that light is made up of photons, whose energy is directly proportional to the frequency of radiation, according to a constant of proportionality, h, which is called Planck's constant. This is expressed by:
E = h*v
where E is the energy, h the Planck constant (whose value is 6.63*10⁻³⁴ J.s) and v the frequency (Hz or s⁻¹).
So the frequency will be:
Being E= 4.91*10⁻¹⁷ J and replacing:
You can get:
v= 7.41*10¹⁶ 
= 7.41*10¹⁶ Hz
<u><em>The frequency of the photon is 7.41*10¹⁶ Hz</em></u>
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