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Assoli18 [71]
3 years ago
12

Im Stuck In This Thing Called ''Life" Can You Help Me.

Physics
2 answers:
lora16 [44]3 years ago
8 0
I'll be willing to help
pantera1 [17]3 years ago
4 0

im still trying to find someone who can help me

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An object is placed 10 cm in front of a diverging mirror. What is the focal length of the mirror if the image appears 2 cm behin
Dafna1 [17]

Answer:

the focal length of the mirror is :  f=-2.5\,\,cm

Explanation:

Use the formula for the formation of image using a divergent mirror and recalling that the image (s') that this mirror formed is virtual, so it is entered as a negative number in the formula. Use the object position (s) as 10, the image position (s') as -2, and derive the value of the focal length:

\frac{1}{s} +\frac{1}{s'}=\frac{1}{f}\\\frac{1}{10} +\frac{1}{-2}=\frac{1}{f}\\\frac{1}{10} -\frac{1}{2}=\frac{1}{f}\\\frac{10\,f}{10} -\frac{10\,f}{2}=\frac{10\,f}{f}\\f-5\,f=10\\-4\,f=10\\f=-2.5\,\,cm

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Which of the following is not in the form of waves?
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What type of relationship exists between acceleration and mass?
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Here, you can derive that by numerical method, as follows:
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Hope this helps!
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