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vovikov84 [41]
3 years ago
13

The block in the illustration is floating in water. Water has a density of 1.0 g/cm 3 and about 25 percent of the block is below

water. What is a good estimate of the density of the block?
Physics
2 answers:
expeople1 [14]3 years ago
7 0
0.75 g/cm3 

let me know if I'm right~! =^-^=  hope it helps~!

~Cecildoesscience
jonny [76]3 years ago
3 0

Answer;

0.25 g/cm^3

Explanation;

25 % of 1 g/cm^3

=  0.25 g/cm^3

Water's density is 1 g/ml. Objects with a density greater than 1g/ml will sink when placed in water.

Objects with a density less than one will float when placed in water. If a block has a density of 0.1g/cm3 it will float because it's density is less than 1.

The percent of the block that will be below the water depends on the density of the floating object. To find the percentage of the object below the water we just convert the density of the object as a percentage.

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Answer:

490.5 N

Explanation:

Coefficient of friction is 0.5 since friction force is set to halfway between none and lots. Minimum force is given by multiplying the weight and coefficient of friction

F= kN where k is coefficient of friction while N is weight. Also, N=mg where m is mass and g is acceleration due to gravity.

F=kmg=0.5*100*9.81=490.5 N

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3 years ago
____ is a chemical messenger released by virus infected cells
MaRussiya [10]

Answer:

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2 years ago
State one advantage and disadvantage of friction
yuradex [85]

Answer:

  1. Advantage: Helps us to walk without slipping.
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Disadvantage:

  1. We slip on a wet floor.
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5 0
2 years ago
A cyclist accelerates from a velocity of 10 miles/hour east until reaching a velocity of 20 miles/hour east in 5 seconds. What w
Sliva [168]

Answer:

a = 0.894\ m/s^2

Explanation:

<u>Motion with Constant Acceleration</u>

A body moves with constant acceleration when the speed changes uniformly in time. The equation used to find the final speed vf is

v_f=v_o+at

Where vo is the initial speed, a is the acceleration, and t is the time.

The cyclist has an initial speed of vo=10 miles/hour and ends up at vf=20 miles/hour in t=5 seconds.

Both speeds are given in miles/hour and we must convert it to m/s:

1 mile/hour = 0.44704 m/s

10 mile/hour = 4.47 m/s

20 mile/hour = 8.94 m/s

The acceleration is calculated by solving for a:

\displaystyle a=\frac{v_f-v_o}{t}

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3 0
2 years ago
The flywheel is rotating with an angular velocity ω0 = 2.37 rad/s at time t = 0 when a torque is applied to increase its angular
nika2105 [10]

Answer:

ω = 12.023 rad/s

α = 222.61 rad/s²

Explanation:

We are given;

ω0 = 2.37 rad/s, t = 0 sec

ω =?, t = 0.22 sec

α =?

θ = 57°

From formulas,

Tangential acceleration; a_t = rα

Normal acceleration; a_n = rω²

tan θ = a_t/a_n

Thus; tan θ = rα/rω² = α/ω²

tan θ = α/ω²

α = ω²tan θ

Now, α = dω/dt

So; dω/dt = ω²tan θ

Rearranging, we have;

dω/ω² = dt × tan θ

Integrating both sides, we have;

(ω, ω0)∫dω/ω² = (t, 0)∫dt × tan θ

This gives;

-1[(1/ω_o) - (1/ω)] = t(tan θ)

Thus;

ω = ω_o/(1 - (ω_o × t × tan θ))

While;

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Thus, plugging in the relevant values;

ω = 2.37/(1 - (2.37 × 0.22 × tan 57))

ω = 12.023 rad/s

Also;

α = (2.37² × tan 57)/(1 - (2.37 × 0.22 × tan 57))²

α = 8.64926751525/0.03885408979 = 222.61 rad/s²

6 0
3 years ago
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