Answer:
11m
Explanation:
Given:
Resistivity ρ = 5.6e-8 Ωm
Radius r = 0.045 mm 
= 4.5 x 10⁻⁵ m
Voltage V = 120V
Current I = 1.24A
From Ohm's law, 
R = 96.77 Ω
Resistivity = (Resistance × Area)/ length
ρ = (RA)/L
Therefore, the length of a wire is given by;
L = (RA)/ρ
Calculating the area A of the wire;
A = πr²
A = π × (4.5 x 10⁻⁵)²
A = 6.36 x 10⁻⁹ m²
Substituting area of the wire A = 6.36 x 10⁻⁹ m² into the equation of the length of wire
L = (96.77 × 6.36×10⁻⁹ ) / 5.6×10⁻⁸
L = 10.9977m
L = 11m (approximately)
If you mean the tree, evergreen trees can exploded if theres extreme stress on the trunk
Answer:
<em>2 m/s</em>
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Explanation:
The electromagnetic flow-metre work on the principle of electromagnetic induction. The induced voltage is given as
where 
is the induced voltage = 2.88 mV = 2.88 x 10^-3 V
is the distance between the electrodes in this field which is equivalent to the diameter of the tube = 1.2 cm = 1.2 x 10^-2 m
is the velocity of the fluid through the field = ?
is the magnetic field = 0.120 T
substituting, we have
2.88 x 10^-3 = 0.120 x 1.2 x 10^-2 x
2.88 x 10^-3 = 1.44 x 10^-3 x
= 2.88/1.44 = <em>2 m/s</em>
Answer:
the object has least potential energy at mean position of the SHM
Explanation:
If a block is connected with a spring and there is no resistive force on the system
In this case the total energy of the system is always conserved and it will change from one form to another form
So here we will say that
Kinetic energy + Potential energy = Total Mechanical energy
As we can say that total energy is conserved so here we have least potential energy when the system has maximum kinetic energy
So here we also know that at mean position of the SHM the system has maximum speed and hence maximum kinetic energy.
So the object has least potential energy at mean position of the SHM
Answer:
400m
Explanation:
If An athlete completes one round of circular track of diameter 200 meter in 40 sec, we can write;
200m = 40sec
To determine the distance after 2min 20secs, we can write;
x = 2,min 20sec
x = 80sec
Divide both expression
200/x = 40/80
200/x = 1/2
x = 2×200
x = 400m
Hence the distance covered after 2min 20secs is 400m
