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3 years ago

If m=120kg and a=15m/s2, what is the force

Physics

1 answer:

Scorpion4ik [409]3 years ago

6 0

Answer:

F= 1800N

Explanation:

the equation for force is F= ma

so plug in the numbers: F= (120)(15)

solve this to get F= 1800N

tip: don't forget to add the units when writing your answer :)

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I believe the answer is coal

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3 years ago

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What is the kinetic energy of the ball just before it hits the ground?

Alex_Xolod [135]

Answer:

$0.5mv^{2}$

Explanation:

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Can you find a vector quantity that has a magnitude of zero but components that are not zero? Explain. Can the magnitude of a ve

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3 years ago

A force is applied to an ideal spring (initially in its equilibrium position) and does 1.9 JJ of work stretching it 2.2 cmcm . H

Verdich [7]

Answer:

W=16.58J

Explanation:

initial information we have

work: $W=1.9J$

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$W=\frac{1}{2} kx^2$

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and clearing for k:

$k=\frac{2(1.9J)}{0.022^2} \\k=7,851.24$

and now we want to know how much work is done when we stretch the spring a distance of 6.5cm from equilibrium, so now x is:

$x=6.5cm=0.065m$

and using the same formula for work, with the value of k that we just found:

$W=\frac{1}{2} kx^2$

$W=\frac{1}{2}(7851.24)(0.065)^2\\W=16.58J$

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3 years ago

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asambeis [7]

The ball rolled for 13.2 s

<h3>Further explanation</h3>

Speed is scalar and no direction

$\tt avg~speed=\dfrac{total~distance}{elapsed~time}=\dfrac{\Delta x}{\Delta t}$

A bowling ball rolls 33 m, with average speed = 2.5 m/s

So elapsed time :

$\tt t=\dfrac{33~m}{2.5`m/s}=13.2~s$

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3 years ago