A block of mass 4 kg slides down an inclined plane inclined at an angle of 30o with the horizontal. Find the acceleration of the
1 answer:
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Answer:
The net torque on the square plate is 2.72 N-m.
Explanation:
Given that,
Side = 0.2 m
Force
Force
Force
We need to calculate the torque due to force F₁
Using formula of torque
Put the value into the formula
We need to calculate the torque due to force F₂
Using formula of torque
Put the value into the formula
We need to calculate the torque due to force F₃
Using formula of torque
Put the value into the formula
We need to calculate the net torque on the square plate
Hence, The net torque on the square plate is 2.72 N-m.
Answer:
51.96 m/s^-1
Explanation:
a) see the attachment
b) As we know the velocity of the projectile has two component, horizontal velocity v_ox. and vertical velocity v_oy as shown in the figure. At the highest point of the trajectory, the projectile has only horizontal velocity and vertical velocity is zero. Therefore at the highest point of the trajectory, the velocity of the projectile will be
v_ox=v_o*cosФ
=60*cos (30)
= 51.96 m/s^-1
