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FromTheMoon [43]
3 years ago
8

A block of mass 4 kg slides down an inclined plane inclined at an angle of 30o with the horizontal. Find the acceleration of the

block a) assuming no friction between the block and the plane. b) in the presence of friction given that coefficient of kinetic friction between block and the plane is 0.4.
Physics
1 answer:
Nataly [62]3 years ago
8 0

Answer:

a) a = 4.9 m/s²

b) a = 1.5 m/s²

Explanation:

no friction

F = ma

gsinθ = ma

a = gsinθ

a = 9.8sin30

a = 4.9 m/s²

friction

gsinθ - μmgcosθ = ma

a = g(sinθ - μcosθ)

a = 9.8(sin30 - 0.4cos30)

a = 1.5051...

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A hockey puck on a frozen pond is given an initial speed of 20.0 m/s. If the puck always remains on the ice and slides 115 m bef
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Answer:

μ_k = 0.1773

Explanation:

We are given;

Initial velocity;u = 20 m/s

Final velocity;v = 0 m/s (since it comes to rest)

Distance before coming to rest;s = 115 m

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v² = u² + 2as

Making a the subject, we have;

a = (v² - u²)/2s

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a = -400/230

a = -1.739 m/s²

From the question, the only force acting on the puck in the x direction is the force of friction. Since friction always opposes motion, we see that:

F_k = −ma - - - (1)

We also know that F_k is defined by;

F_k = μ_k•N

Where;

μ_k is coefficient of kinetic friction

N is normal force which is (mg)

Since gravity acts in the negative direction, the normal force will be positive.

Thus;

F_k = μ_k•mg - - - (2)

where g is acceleration due to gravity.

Thus,equating equation 1 and 2,we have;

−ma = μ_k•mg

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