Its tangential speed is constant although its velocity is changing. As the object changes direction, it results in a changing of positive and negative signs of the velocity. Although, the magnitude of the velocity (speed) is not changing.
The answers false I believe
Explanation:
V=u+at
where,
v=final speed
u=initial speed,(starting speed)
a=acceleration
t=time
- v=u+at = 6=2+a*2
6=2+2a
2a=6-2
2a=4
a=4/2 = 2
a =2
2. to find time taken
v=u+at
25=5*2t
2t=25-5
2t=20
t=20/2
t=10sec
3. finding final speed
v=u+at
v=4+10*2
=4+20
v=24m/sec
5.v=u+at
=5+8*10
=5+80
V=85m/sev
6. v=u+at
8=u+4*2
8=u+8
U=8/8
u=1
these are your missing values
Answer:

Explanation:
If we have a periodic wave we need to satisfy the following basic relationship:

From the last formula we see that the velocity is proportional fo the frequency.
For this case we have the following info given by the problem:

We know that the frequency is the reciprocal of the period so we have this formula:

And if we replace we got:

Now since we have the value for the wavelength we can find the velocity like this:

And if we convert this into cm/s we got:
