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Keith_Richards [23]
4 years ago
7

In the United States, volume of irrigation water is usually expressed in acre-feet. One acre-foot is a volume of water sufficien

t to cover 1 acre of land to a depth of 1 ft (640 acres = 1 mi2, 1 mi = 5280 ft). The principal lake in the California Water Project is Lake Oroville, whose water storage capacity is listed as 3.54 x 106 acre-feet. Express the volume of Lake Oroville in (a) cubic feet, (b) cubic meters, and (c) US gallons.
Chemistry
1 answer:
gavmur [86]4 years ago
6 0

Answer:

a) V = 1.542 E11 ft³

b) V = 4367011968 m³

c) V = 1.1535 E12 us gal

Explanation:

Acre surface is defined as 66 by 660 feet at a depth of one foot:

⇒ Vacre-foot = 66ft*660ft*1ft = 43560 ft³

lake:

a)  V = 3.54 E6 acre-feet * ( 43560 ft³ / acre-foot ) = 1.542 E11 ft³

b) V = 1.542 E11 ft³ * ( 0.02832m³ / ft³ ) = 4367011968 m³

c) V = 1.542 E11 ft³ * ( 7.48052 us gal/ft³ ) = 1.1535 E12 us gal

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astraxan [27]

Answer is: 4) The same subscripts are on each side of the equation.

For example, balanced chemical reaction:

2Mg + O₂ → 2MgO.

1) The same number of atoms is on each side of the equation: two magnesium atoms and two oxgen atoms.

2) The formulas for all substances are correct: in magnesium oxide (MgO), magnesium has oxidation number +2 and oxygen -2, so formula is good, because compound must be neutral.

3) The same mass is represented on each side of the equation: because there is same number of atoms, the mass is the same.

4) The same subscripts are on each side of the equation: oxygen does not have same subscripts.

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4 years ago
Which law relates to the ideal gas law?
professor190 [17]

<u>Answer:</u> The law that related the ideal gas law is \frac{V_1}{n_1}=\frac{V_2}{n_2}

<u>Explanation:</u>

There are 4 laws of gases:

  • <u>Boyle's Law:</u> This law states that pressure is inversely proportional to the volume of the gas at constant temperature.  

Mathematically,

P_1V_1=P_2V_2

  • <u>Charles' Law:</u> This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

  • <u>Gay-Lussac Law:</u> This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

  • <u>Avogadro's Law:</u> This law states that volume is directly proportional to number of moles at constant temperature and pressure.

Mathematically,

\frac{V_1}{n_1}=\frac{V_2}{n_2}

Hence, the law that related the ideal gas law is \frac{V_1}{n_1}=\frac{V_2}{n_2}

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4 years ago
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Answer to the question

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6 0
3 years ago
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What is emperical formula of 62.4% C 4.19 % H 33.2% O
Wittaler [7]

Answer:

C_{26}H_{21}O_{10}

Explanation:

We are given the following percentages:

Carbon ------ 62.4%

Hydrogen ------------ 4.19%

Oxygen ---------------- 33.2%

Now, let's take a 100g sample of this compound

since percentages are calculated out of 100, you will notice that the mass of the elements in the sample is the same as their percent composition

So we have:

Carbon -------- 62.4 grams

Hydrogen ----------- 4.19 grams

Oxygen ------------ 33.2 grams

With this information, we can calculate the number of moles of the respective elements in the given compound

Moles of Carbon (mass = 12u):

Given mass / Molar mass = 62.4 / 12 = 5.2 moles

Moles of Hydrogen (mass = 1u):

Given mass / Molar mass = 4.19 / 1 = 4.2 moles (approx)

Moles of oxygen (mass = 16u):

Given mass / Molar mass = 33.2 / 16 = 2 moles

The ratio of moles of the respective elements in our compound:

(Moles of Carbon)  :    (Moles of Hydrogen)   :  (Moles of Oxygen)

5.2   :     4.2   :    2

Which can be written as:    C_{5.12} H_{4.2} O_{2}

We are almost done but there is one problem, the formulas of compounds we see have whole numbers and not decimals

So, we will multiply all 3 of the numbers by the smallest number possible to get whole number ratios

Since there are 2 numbers we need to take care of and both of them have 2 in the decimal place,

we can multiply by 5 to get whole number ratios

So we get:

26   :    21   :    10

Therefore the molecular formula of the compound:

C_{26}H_{21}O_{10}

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4 years ago
What is the value of n in CH3(CH2)nCH3 if the name of the hydrocarbon is heptane
LekaFEV [45]

Answer:

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How many carbon atoms in total in this straight-chain hydrocarbon?

The prefix of the IUPAC name of a hydrocarbon (the part before -ane) shows the number of carbon atoms on the longest carbon chain.

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  • Prefix: hept-;
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Hence the structure:

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\text{CH}_3\text{-}{(\text{CH}_2)_{\bf5}\text{-CH}_3.

Therefore n = 5.

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4 years ago
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