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Ipatiy [6.2K]
3 years ago
15

What is the value of n in CH3(CH2)nCH3 if the name of the hydrocarbon is heptane

Chemistry
2 answers:
Ksenya-84 [330]3 years ago
5 0

Answer:

n+5 so the correct answer is b) 5

Explanation:

just did review on edge

LekaFEV [45]3 years ago
4 0

Answer:

n = 5.

Explanation:

How many carbon atoms in total in this straight-chain hydrocarbon?

The prefix of the IUPAC name of a hydrocarbon (the part before -ane) shows the number of carbon atoms on the longest carbon chain.

\begin{array}{c|c}\text{Number of Carbon}\\ \text{atoms in backbone} & \text{Prefix}\\[-0.5em]\multicolumn{2}{c}{\rule{5cm}{0.5pt}}\\1& \text{meth-} \\ 2&\text{eth-} \\ 3&\text{prop-}\\4 & \text{but-}\\5 & \text{pent-} \\ 6 & \text{hex-} \\ 7 & \text{hept-} \\8 & \text{oct-}\\ \dots & \dots\end{array}.

  • Name of this hydrocarbon: heptane;
  • Prefix: hept-;
  • Number of carbon atoms in the longest chain: 7.

Hence the structure:

\text{CH}_3\text{-CH}_2\text{-CH}_2\text{-CH}_2\text{-CH}_2\text{-CH}_2\text{-CH}_3.

All the \text{-CH}_2\text{-} in the formula might look redundant. "\text{CH}_2" appears five times in a row and may be condensed into (\text{CH}_2)_5. Hence the condensed formula:

\text{CH}_3\text{-}{(\text{CH}_2)_{\bf5}\text{-CH}_3.

Therefore n = 5.

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3 years ago
Determine the empirical formula of the following compound if a sample contains 0.104 molK, 0.052 molC, and 0.156 molO;?
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Answer:

K₂CO₃    

Explanation:

Given parameters:

Number of moles of K = 0.104mol

Number of moles of C = 0.052mol

Number of moles of O = 0.156mol

Method

From the given parameters, to calculate the empirical formula of the elements K, C and O, we reduce the given moles to the simplest fraction.

Empirical formula is the simplest formula of a compound and it differs from the molecular formula which is the actual formula of a compound.

  • Divide the given moles through by the smallest which is C, 0.052mol.
  • Then approximate values obtained to the nearest whole number of multiply by a factor to give a whole number ratio.
  • This is the empirical formula

Solution

Elements                             K                       C                    O

Number of moles            0.104                0.052            0.156

Dividing by the

smallest                       0.104/0.052     0.052/0.052  0.156/0.052

                                            2                           1                     3

The empirical formula is K₂CO₃      

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