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3 years ago

Can someone give me some info about volcanoes but like if you were telling the in formation to a kid

1 answer:

7 0

Umm the rocks warm up until it becomes a not rock anymore and becomes really hot then it get so hot it starts coming out of a mountain called a volcanoe

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2) What does the specific heat capacity of a material tell you about how easy it is to heat up

Fed [463]

Answer:

High specific heat -> takes more energy to raise/lower object's temperature

Low specific heat -> takes less energy to raise/lower object's temperature

Explanation:

The specific heat capacity is the amount of heat required to raise the temperature of something per unit of mass.

A high specific heat value for an object means it takes more energy to raise or lower that object's temperature. A low specific heat value for an object means it does not take very much energy to heat or cool that object.

6 0

3 years ago

For photons of 50 keV, 500 keV, and 5 MeV, what will be the most likely init interaction with tissue?

love history [14]

Answer:

50 KeV

Explanation:

50 KeV will be the most likely initial interaction with tissue.

Because Higher the energy lesser will the interaction with tissues, Because it will penetrate through tissue more easily in a very lesser time Whereas the photon with least energy will take more time to penetrate through the tissue, hence, higher interaction with tissue.

3 0

3 years ago

How many kilometers are in 1.40 miles

ELEN [110]

The answer is 2.25308 km

4 0

3 years ago

An electron is located on a pinpoint having a diameter of 3.52 µm. What is the minimum uncertainty in the speed of the electron?

Komok [63]

Explanation:

It is given that,

An electron is located on a pinpoint having a diameter of 3.52 µm, $\Delta x=3.52\times 10^{-6}\ m$

We need to find the minimum uncertainty in the speed of the electron. It can be calculated using Heisenberg uncertainty principal as :

$\Delta p.\Delta x \geq \dfrac{h}{4\pi}$

$\Delta p \geq \dfrac{h}{4\pi \Delta x}$

Since, p = m v

So, $mv \geq \dfrac{h}{4\pi \Delta x}$

$\Delta v \geq \dfrac{h}{4\pi \Delta x m}$

$\Delta v \geq \dfrac{6.67\times 10^{-34}}{4\pi 3.52\times 10^{-6}\times 9.1\times 10^{-31}}$

$\Delta v\geq 16.57\ m/s$

So, the minimum uncertainty in the speed of the electron is greater than 16.57 m/s. Hence, this is the required solution.

5 0

3 years ago

The formula v = √2.5r models the maximum safe speed, v, in miles per hour, at which a car can travel on a curved road with radiu

mel-nik [20]

Answer:

The maximum safe speed of the car is 30.82 m/s.

Explanation:

It is given that,

The formula that models the maximum safe speed, v, in miles per hour, at which a car can travel on a curved road with radius of curvature r r, is in feet is given by :

$v=\sqrt{2.5\ r}$ .........(1)

A highway crew measures the radius of curvature at an exit ramp on a highway as 380 feet, r = 380 feet

Put the value of r in equation (1) as :

$v=\sqrt{2.5\ \times 380}$

v = 30.82 m/s

So, the maximum safe speed of the car is 30.82 m/s. Hence, this is the required solution.

4 0

3 years ago