We need to know the value of van't hoff factor.
The van't hoff factor is: 2.66 or 2.7 (approximately)
(NH₄)₂SO₄ is an ionic compound, so it dissociates in solution and produces 3 ionic species. Therefore van't hoff factor is more than one.
From the equation: Δ
=i 
.m, where Δ= elevation of boiling point=102.5 - 100=2.5°C.
m=molality of solute=1.83 m (Given)
= Ebullioscopic constant or Boiling point elevation constant= 0.512°C/m (Given)
i= Van't Hoff factor
So, 2.5= i X 0.512 X 1.83
i=
i=2.66= 2.7 (approx.)
Answer:
Just study the thing don't expect others to just answer the homework for you
Explanation:
If you truly are a good student then you should have asked your teacher in person or through email instead of asking on here. Not trying to be mean but you also have to understand that people on here have a life. :)
Sorry I’m not sure sksnsnsns. Sksnsnsnsnss sksnsnsnsnsnssnsnsns
Mass is density times volume
0.760 x 531 = 403.56g
404g if 3 sig figs
