Given :
Number of moles , n = 36.25 mol .
Molarity , M = 1.25 M .
To Find :
The volume of water required .
Solution :
Moarity is given by :
So , 
Here , n is number of moles and M is molarity .
Putting all values in above equation , we get :
Therefore , volume of water required is 29 L .
Answer:
The acid-base reaction produces glycine reduction, and hence the increase of glycine pH.
Explanation:
The glycine is an amino acid with the following chemical formula:
NH₂CH₂COOH
The COOH functional group is what gives the acid properties in the molecule.
Hence, when NaOH is added to glycine an acid-base reaction takes place in which COOH reacts with the NaOH added:
NH₂CH₂COOH + OH⁻ ⇄ NH₂CH₂COO⁻ + H₂O
The glycine concentration starts to shift to its ion form (NH₂CH₂COO⁻) because of the reaction with NaOH, that is why the pH glycine increases when NaOH is added.
Therefore, the acid-base reaction produces glycine reduction, and hence the increase of glycine pH.
I hope it helps you!
Answer:
Mole fraction of 
= 0.58
Mole fraction of 
= 0.42
Explanation:
Let the mass of and = x g
Molar mass of = 33.035 g/mol
The formula for the calculation of moles is shown below:
Thus,
Molar mass of = 46.07 g/mol
Thus,
So, according to definition of mole fraction:
Mole fraction of = 1 - 0.58 = 0.42
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