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3 years ago

What are some chemical formulas for compounds?

Chemistry

1 answer:

Galina-37 [17]3 years ago

4 0

Hello there!

First, we need to know what compounds are.
Compounds "are pure substances that are made up of two or more elements that are chemically combined in fixed mass ratios."

Now we need to understand what chemical formulas are.
The compounds have a chemical formula which tell us that
a) the elements that are present in the compound
b) the ratio of these elements in the compound

What are some chemical formulas for compounds?
Well, we start with water. The chemical formula for water is H2O

When we go back to the definition of compounds, it says it is when a pure substance that are made up two or more elements. So, whatever is a pure substance and it's made up of two elements. These elements are Hydrogen and Oxygen. And keep an mind that water is made up with metal plus non-metal.

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Here are one more chemical formulas for compounds
Sodium Chloride = NaCI

I included a picture that might help you too. (Credit to google image)

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How many grams of product can be produced by reacting 5.0 gram of aluminum and 22 grams of bromine? 2 Al + 3 Br2 > 2 AlBr3

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Answer:

The mass of AlBr3 is 24.5 grams

Explanation:

Step 1: Data given

Mass of aluminium = 5.0 grams

Mass of bromine = 22.0 grams

Molar mass of aluminium = 26.98 g/mol

Molar mass of br2= 159.8 g/mol

Step 2: The balancced equation

2 Al + 3 Br2 → 2 AlBr3

Step 3: Calculate moles Al

Moles Al = mass Al / molar mass Al

Moles Al = 5.0 grams / 26.98 g/mol

Moles Al = 0.185 moles

Step 4: Calculate moles Br

Moles Br = 22.0 grams / 159.8 g/mol

Moles Br = 0.138 moles

Step 5: Calculate limiting reactant

For 2 moles Al we need 3 moles Br2 to produce 2 moles AlBr3

Br2 is the limiting reactant. It will completely be consumed (0.0313 moles)

Al is in excess. There will react 2/3*0.138 = 0.092 moles

There will remain 0.185- 0.092 = 0.093 moles Al

Step 6: Calculate moles AlBr3

For 2 moles Al we need 3 moles Br2 to produce 2 moles AlBr3

For 0.0313 moles Br2 we'll have 2/3*0.138 = 0.092 moles AlBr3

Step 7: Calculate mass AlBr3

Mass AlBr3 = moles * molar mass

Mass AlBr3 = 0.092 moles * 266.69 g/mol

Mass AlBr3 = 24.5 grams

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