Answer:
Molecular formula = C₆H₁₂O₆
Explanation:
Given data:
Mass of hydrogen = 31.7 g
Mass of carbon = 283.4 g
Mass of oxygen = 377.4 g
Molar mass of compound = 176.124 g/mol
Molecular formula = ?
Solution:
Number of gram atoms of H = 31.7 / 1.01 = 31.4
Number of gram atoms of O = 377.4 / 16 = 23.6
Number of gram atoms of C = 283.4 / 12 = 23.6
Atomic ratio:
C : H : O
23.6/23.6 : 31.4/23.6 : 23.6/23.6
1 : 1.33 : 1
C : H : O =3 (1 : 1.33 : 1
)
Empirical formula is C₃H₄O₃.
Molecular formula:
Molecular formula = n (empirical formula)
n = molar mass of compound / empirical formula mass
Empirical formula mass = 3×12+4+3×16 = 88
n = 176.124 / 88
n = 12
Molecular formula = n (empirical formula)
Molecular formula = 2 (C₃H₄O₃)
Molecular formula = C₆H₁₂O₆
Chemical senses require moisture, or water, for transduction to occur.
Glaciers are found in areas where the net accumulation of snow exceeds the melt, therefore they are usually found in areas of high elevation, cold temperatures, and high precipitation.
Geysers are found in areas of shallow crust with high heat flow, such as hot spots.
Answer:
Because Rutherford's model was weak on the position of the electrons, Bohr focused on them. He hypothesized that electrons can move around the nucleus only at fixed distances from the nucleus based on the amount of energy they have. ... However, an electron could never exist in between two energy levels
Nitrogen (N2) and hydrogen (H2) gases react to form ammonia, which requires -99.4 J/K of standard entropy (ΔS°).
What is standard entropy?
The difference between the total standard entropies of the reaction mixture and the summation of the standard entropies of the outputs is the standard entropy change. Each entropy in the balanced equation needs to be compounded by its coefficient, as shown by the letter "n."
Calculation:
Balancing the given reaction following-
1/2 N₂(g) + 3/2 H₂ (g)→ NH₃ (g)
ΔS° = [1 mol x S° (NH₃)g] - [1/2 mol x S° (N₂)g] - [3/2 mol x S°(H₂)g]
Here S° = standard entropy of the system
Insert into the aforementioned equation all the typical entropy values found in the literature:
ΔS° = [1 mol x 192.45 J/mol.K] - [1/2 mol x 191.61 J/mol.K] - [3/2 mol x 130.684 J/mol.K]
⇒ΔS° = - 99.4 J/K
Therefore, the standard entropy, ΔS° is -99.4 J/K.
Learn more about standard entropy here:
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