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kirill115 [55]
3 years ago
7

If a girl is running along a straight road with uniform velocity 1.5 m/s, what is her acceleration?​

Physics
1 answer:
artcher [175]3 years ago
7 0

Answer:

0 m/s²

Explanation:

Acceleration is change in velocity over time.  The velocity is constant, so the acceleration is 0.

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Which of the following best describes a hypothesis?
ololo11 [35]
I am 99% sure it is B :)
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Please help!!! I have a physics exam tomorrow and I just can't wrap my head around this one!
Ainat [17]

The total electrostatic force on charge A is 28 \mu N

Explanation:

The magnitude of the electrostatic force between two charges is given by Coulomb's law:

F=k\frac{q_1 q_2}{r^2}

where:

k=8.99\cdot 10^9 Nm^{-2}C^{-2} is the Coulomb's constant

q_1, q_2 are the two charges

r is the separation between the two charges

Here we have three positively charged particles A,B and C, located at the following positions:

x_A = 0\\x_B = 10 m\\x_C = 20 m

The magnitudes of the three charges are:

q_A = q_B = q_C = 0.5 \mu C = 0.5\cdot 10^{-6}C

The force exerted by B on A is to the left (because the force between two positive charges is repulsive), and the force exerted by C on A is also to the left (also repulsive). Therefore, the net force on A is just the sum of the two forces exerted by charges B and C:

F_A = F_{BA} + F_{CA} = k\frac{q_B q_A}{(x_B-x_A)^2}+k\frac{q_C q_A}{(x_C-x_A)^2}=\\=(8.99\cdot 10^9) \frac{(0.5\cdot 10^{-6})^2}{(10)^2}+(8.99\cdot 10^9) \frac{(0.5\cdot 10^{-6})^2}{(20)^2}=2.8\cdot 10^{-5} N = 28 \mu N

Learn more about electric force:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

3 0
3 years ago
HELP IM IN A EXAM!!!
natali 33 [55]
Answer:

Species A and C

Explanation: none
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3 years ago
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4 years ago
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Marybeth and Grant are pushing on a wagon, both pushing in opposite directions. Marybeth is pushing to the left with a force of
Vladimir [108]

Answer:

14 N to the right

Explanation:

The net force is equal to the resultant of the forces acting on the wagon. In this case, we are considering two forces acting on the wagon:

- The force applied by Marybeth, to the left, of magnitude 34 N

- The force applied by Grant, to the right, of magnitude 48 N

Since the two forces are in opposite directions, in order to find the net force, we must choose a positive direction. Let's take "right" as positive direction, so the net force is:

F=+48 N-34 N=+14 N

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