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mars1129 [50]
3 years ago
7

A car starts moving from the position of rest with uniform acceleration of 8m/s^calculate the distance travelled by it during 10

th minute of its motion.
Physics
1 answer:
ad-work [718]3 years ago
8 0

We calculate the coordinates at t₁ = 9 min and t₂ = 10 min, since the 10th minute is between t₁ and t₂.

As it leaves from rest, it means that the initial speed is zero


t₁=9 min=540 s

t₂=10 min=600 s

x₁=at₁²/2=8*540²/2=4*291600=1166400 m

x₂=at₂²/2=8*600²/2=4*360000=1440000 m

Δx=x₂-x₁=1440000-1166400=273600 m represents the distance traveled by the car in the 10th minute of travel




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