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3 years ago

Why must you use temperature to specify how hot or cold something is?

2 answers:

7 0

At others time we need to k ow how hot or cold something is when we need to measure temperature correctly we need to use an instrument called a thermometer this measure temperature in degrees Celsius or degrees Fahrenheit

neonofarm [45]3 years ago

3 0

Explanation:

Well to come to think because using the terms hot and cold can be confusing

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Science please help!

Romashka [77]

<span>Inertia is a property of matter
i hope this help</span>

6 0

3 years ago

Read 2 more answers

You exert 500 N of force down on the earth as you jump into the air. How much force does the earth exert back on you?

zalisa [80]

The same 500N, is the Newton’s Third Law.

6 0

3 years ago

A unit for measuring frequency is the

jonny [76]

A.) Hertz is the measuring unit for frequency!!
[Your explanation is correct]

Hope this helps!

4 0

4 years ago

Calculate the acceleration of gravity as a function of depth in the earth (assume it is a sphere). You may use an average densit

Ber [7]

Solution :

Acceleration due to gravity of the earth, g $=\frac{GM}{R^2}$

$g=\frac{G(4/3 \pi R^2 \rho)}{R^2}=G(4/3 \pi R \rho)$

Acceleration due to gravity at 1000 km depths is :

$g=G\left(\frac{4}{3}\pi (R-d) \rho\right)$

$g=6.67 \times 10^{-11}\left(\frac{4}{3}\times 3.14 \times (6371-1000) \times 5.5 \times 10^3\right)$

$= 822486 \times 10^{-8}$

$=0.822 \times 10^{-2} \ km/s$

= 8.23 m/s

Acceleration due to gravity at 2000 km depths is :

$g=G\left(\frac{4}{3}\pi (R-d) \rho\right)$

$g=6.67 \times 10^{-11}\left(\frac{4}{3}\times 3.14 \times (6371-2000) \times 5.5 \times 10^3\right)$

$= 673552 \times 10^{-8}$

$=0.673 \times 10^{-2} \ km/s$

= 6.73 m/s

Acceleration due to gravity at 3000 km depths is :

$g=G\left(\frac{4}{3}\pi (R-d) \rho\right)$

$g=6.67 \times 10^{-11}\left(\frac{4}{3}\times 3.14 \times (6371-3000) \times 5.5 \times 10^3\right)$

$= 3371 \times 153.86 \times 10^{-8}$

= 5.18 m/s

Acceleration due to gravity at 4000 km depths is :

$g=G\left(\frac{4}{3}\pi (R-d) \rho\right)$

$g=6.67 \times 10^{-11}\left(\frac{4}{3}\times 3.14 \times (6371-4000) \times 5.5 \times 10^3\right)$

$= 153.84 \times 2371 \times 10^{-8}$

$=0.364 \times 10^{-2} \ km/s$

= 3.64 m/s

3 0

3 years ago

Which of the following choices concerning the net magnetic flux through any enclosed surface is true according to Gauss' law for

11Alexandr11 [23.1K]

Answer:

e. The net magnetic flux in this case would be equal to zero.

Explanation:

As per Gauss law of magnetism we need to find the net magnetic flux through a closed loop

here we know that net magnetic flux is the scalar product of magnetic field vector and area vector

so here we have

$\int B. dA$ = net magnetic flux

since we know that magnetic field always forms closed loop so if we find the integral over a closed loop

then in that case the value of the close integral must be zero

so correct answer would be

e. The net magnetic flux in this case would be equal to zero.

6 0

3 years ago