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Lemur [1.5K]
3 years ago
8

If Angela ran to the bus and back to where she started what distance would she travel ?

Physics
1 answer:
Yakvenalex [24]3 years ago
5 0

Answer:

Distance = 30 m

Explanation:

Since the position of the bus is at zero, and distance is a scalar quantity. That is, we are only concerned about the magnitude

If Angela ran to the bus and back to where she started, the distance travelled will be:

Distance = 15 + 15 = 30 m

But her displacement will be:

Displacement = 15 - 15 = 0.

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What’s the acceleration if the average velocity is 3.5 and the time is 8.7
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Which mixtures could be separated using evaporation? Check all that apply. fat in milk salt in ocean water mud in pond water but
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4 years ago
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An object is moving at a constant speed along a straight line. Which of the following statements is not true? A. There must be a
Svetradugi [14.3K]

Answer:

False statement = There must be a non-zero net force acting on the object.  

Explanation:

An object is moving at a constant speed along a straight line. If the speed is constant then its velocity must be constant. We know that the rate of change of velocity is called acceleration of the object i.e.

a=\dfrac{dv}{dt}

a = 0

⇒ The acceleration of the object is zero.

The product of force and acceleration gives the magnitude of force acting on the object i.e.

F = m a = 0

⇒  The net force acting on the object must be zero.

So, the option (a) is not true. This is because the force acting on the object is zero. First option contradicts the fact.

6 0
4 years ago
A square loop of side 7 cm is placed with the nearest side 2 cm from a long wire carrying a current that varies with time at a c
ioda

Answer:

Explanation:

side of the square loop, a = 7 cm

distance of the nearest side from long wire, r = 2 cm = 0.02 m

di/dt = 9 A/s

Integrate on both the sides

\int _{0}^{i}di =9\int _{0}^{t}dt

i = 9t

(a) The magnetic field due to the current carrying wire at a distance r is given by

B = \frac{\mu_{0}i}{2\pi r}

B = \frac{\mu_{0}\times 9t}{2\pi r}

(b)

Magnetic flux,

\phi=\int B\times a dr

\phi=\int \frac{\mu_{0}\times 9t}{2\pi r}\times a dr

\phi=\frac{\mu_{0}\times 9t\times a}{2\pi}\times ln\left ( \frac{2 + 7}{2} \right )

\phi=\frac{\mu_{0}\times 9t\times 0.07}{2\pi}\times ln(4.5)

\phi = 1.89 \times 10^{-7}t

(c)

R = 3 ohm

e = -\frac{d\phi}{dt}

magnitude of voltage is

e = 1.89 x 10^-7 V

induced current, i = e / R = (1.89 x 10^-7) / 3

i = 6.3 x 10^-8 A

8 0
3 years ago
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