2 C₅H₁₀ (l) + 15 O₂ (g) → 10 CO₂ (g) + 10 H₂O (g)
Explanation:
Balanced chemical equation for combustion of pentane C₅H₁₀:
C₅H₁₀ (l) + (15/2) O₂ (g) → 5 CO₂ (g) + 5 H₂O (g)
to get integer numbers for the stoechiometric coefficients we multiply with 2:
2 C₅H₁₀ (l) + 15 O₂ (g) → 10 CO₂ (g) + 10 H₂O (g)
where:
(l) - liquid
(g) - gas
Learn more about:
combustion of hydrocarbons
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A. Filtration
This is because of the layers of Filter it goes through to make sure it is pure.
The correct answer is (C. zirconium - 93.
Answer:
by using a moving solvent on filter paper.
Explanation: