Question

Combustion of hydrocarbons such as pentane (C5H12) produces carbon dioxide, a "greenhouse gas." Greenhouse gases in the Earth's atmosphere can trap the Sun's heat, raising the average temperature of the Earth. For this reason there has been a great deal of international discussion about whether to regulate the production of carbon dioxide. Write a balanced chemical equation, including physical state symbols, for the combustion of liquid pentane into gaseous carbon dioxide and gaseous water.

Answer 1

Answer: The balanced chemical equation is written below.

Explanation:

Combustion reaction is defined as the chemical reaction in which a hydrocarbon reacts with oxygen gas to produce carbon dioxide gas and water molecule.

$\text{Hydrocarbon}+O_2\rightarrow CO_2+H_2O$

The chemical equation for the combustion of pentane follows the reaction:

$C_5H_{12}(l)+8O_2(g)\rightarrow 5CO_2(g)+6H_2O(g)$

By Stoichiometry of the reaction:

1 mole of liquid pentane reacts with 8 moles of oxygen gas to produce 5 moles of carbon dioxide gas and 6 moles of gaseous water.

Hence, the balanced chemical equation is written above.

Answer 2

2 C₅H₁₀ (l) + 15 O₂ (g) → 10 CO₂ (g) + 10 H₂O (g)

Explanation:

Balanced chemical equation for combustion of pentane C₅H₁₀:

C₅H₁₀ (l) + (15/2) O₂ (g) → 5 CO₂ (g) + 5 H₂O (g)

to get integer numbers for the stoechiometric coefficients we multiply with 2:

2 C₅H₁₀ (l) + 15 O₂ (g) → 10 CO₂ (g) + 10 H₂O (g)

where:

(l) - liquid

(g) - gas

Learn more about:

combustion of hydrocarbons

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