There are 6.022 × 10²³ atoms in 39.948 g of argon and 4.0026 g of helium.
Explanation:
39.945 g/mole is the molar mass of argon so 39.948 g of argon are equal to 1 mole of argon.
4.0026 g/mole is the molar mass of helium so 4.0026 g of helium are equal to 1 mole of helium.
We know that Avogadro's number tell us the number of particles in 1 mole of substance which is 6.022 × 10²³.
So in 39.948 g of argon and 4.0026 g of helium contains the same number of atoms, 6.022 × 10²³.
Learn more about:
Avogadro's number
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Answer: 7.79 grams of ethanol were put into the beaker.
Explanation:
To calculate the mass of ethanol, we use the equation:
Density of ethanol = 0.779 g/mL
Volume of water = 10.00 mL
Putting values in above equation, we get:
Thus 7.79 grams of ethanol were put into the beaker.
Answer:
The final electron acceptor of the electron transport chain is oxygen
Explanation:
Four electrons gotten from cytochrome c are involved in the conversion of a molecule of oxygen (O2) to two molecules of water (H2O). This final electron transfer occurs in complex IV. Complex IV, also known as cytochrome c oxidase, facilitates the the use of four protons from the matrix of the mitochondrion, in the production of water molecules while pumping four protons to the intermembrane space of the mitochondrion.
