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Serga [27]
3 years ago
6

If atoms of a halogen nonmetal (Group 17) gains one electron, the atoms the have __.

Chemistry
2 answers:
RUDIKE [14]3 years ago
8 0

Hm, this could be more than one option, but gaining electrons makes a negative charge, so

If atoms of a halogen nonmetal (Group 17) gains one electron, the atoms the have "a negative one charge".

Lady bird [3.3K]3 years ago
4 0

Answer : If atoms of a halogen nonmetal (Group 17) gains one electron, the atoms the have (-1) (or, negative) change.

Explanation :

Periods : A row in the periodic table is known as periods.

The common features about the elements of a period are :

Each periods has elements with the same number of electron shells or energy levels or shell.

They transition from metal to noble gas that means they move from metal to non-metal and then non-metal to noble gas.

Groups : A column in the periodic table is known as groups.

The common features about the elements of a same group are :

Each groups has elements with the same number of valance electrons.

The elements in the same group have similar chemical properties.

The elements in the same group have similar physical properties.

The group 17 is a non-metal and known as halogen. The number of valance electrons present in group 17 are 7 valence electrons.

The general electronic configuration of group 17 is:

ns^2np^5

As per question, when atoms of halogen gains one electron then the  atoms have (-1) (or, negative) charge and attain stable electronic configuration as noble gas.

For example : The element chlorine belongs to group 17 and the electronic configuration is:

1s^22s^22p^63s^23p^5

When chlorine atom gain one electron then the chlorine atom have (-1) charge Cl^-.

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Menthol, the substance we can smell in mentholated cough drops, is composed of c, h, and o. a 9.045×10−2 −mg sample of menthol i
Ket [755]

Answer:

            Empirical Formula  =  C₁₀H₂₀O

Solution:

Data Given:

                      Mass of Menthol  =  9.045 × 10⁻² mg  =  9.045 × 10⁻⁵ g

                      Mass of CO₂  =  0.2546 mg  =  0.0002546 g

                      Mass of H₂O  =  0.1043 mg  =  0.0001043 g

Step 1: Calculate %age of Elements as;

                      %C  =  (mass of CO₂ ÷ Mass of sample) × (12 ÷ 44) × 100

                      %C  =  (0.0002546 ÷ 9.045 × 10⁻⁵) × (12 ÷ 44) × 100

                      %C  =  (2.814) × (12 ÷ 44) × 100

                      %C  =  2.814 × 0.2727 × 100

                      %C  =  76.73 %


                      %H  =  (mass of H₂O ÷ Mass of sample) × (2.02 ÷ 18.02) × 100

                      %H  =  (0.0001043 ÷ 9.045 × 10⁻⁵) × (2.02 ÷ 18.02) × 100

                      %H  =  (1.153) × (2.02 ÷ 18.02) × 100

                      %H  =  1.153 × 0.1120 × 100

                     %H  =  12.91 %


                      %O  =  100% - (%C + %H)

                      %O  =  100% - (76.73% + 12.91%)

                      %O  =  100% - 89.64%

                     %O  =  10.36 %

Step 2: Calculate Moles of each Element;

                      Moles of C  =  %C ÷ At.Mass of C

                      Moles of C  = 76.73 ÷ 12.01

                     Moles of C  =  6.3888 mol


                      Moles of H  =  %H ÷ At.Mass of H

                      Moles of H  = 12.91 ÷ 1.01

                      Moles of H  =  12.7821 mol


                      Moles of O  =  %O ÷ At.Mass of O

                      Moles of O  = 10.36 ÷ 16.0

                      Moles of O  =  0.6475 mol

Step 3: Find out mole ratio and simplify it;

                C                                        H                                     O

            6.3888                              12.7821                            0.6475

     6.3888/0.6475                  12.7821/0.6475                 0.6475/0.6475

               9.86                                   19.74                                   1

             ≈ 10                                      ≈ 20                                     1

Result:

         Empirical Formula  =  C₁₀H₂₀O₁

8 0
3 years ago
A rigid container of O has a pressure of 340 kPa at a temperature of 713 K. What is the pressure at 273 K?
tia_tia [17]

Answer:

P₂ = 130.18 kPa

Explanation:

In this case, we need to apply the Gay-Lussack's law assuming that the volume of the container remains constant. If that's the case, then:

P₁/T₁ = P₂/T₂   (1)

From here, we can solve for the Pressure at 273 K:

P₂ = P₁ * T₂ / T₁   (2)

Now, all we need to do is replace the given data and solve for P₂:

P₂ = 340 * 273 / 713

<h2>P₂ = 130.18 kPa</h2>

Hope this helps

4 0
2 years ago
Which statement about atmospheric pressure is false?
Vinil7 [7]

Answer:

D) With an increase in altitude, atmospheric pressure increases as well.

Explanation:

Generally when altitude increases, the value of pressure decreases. This shows that pressure is inversely proportional to altitude. For example, the higher the altitude, the lower the pressure and vice versa. At very high altitude, the number of molecules of air are smaller than the number of moles of air at very low altitude. Thus, the higher the altitude, the lower the atmospheric pressure and the lower the altitude, the higher the atmospheric pressure. Therefore, option (D) is false.

6 0
3 years ago
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What family has 4 valence electrons?
PilotLPTM [1.2K]

Answer:carbon group

Explanation:

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2 years ago
True or False <br> the way energy flows through an ecosystem can be shown through a food web
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True energy passes from animal to animal or plant to plant
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3 years ago
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