2.5gm answer ....2/18x22.5
Answer:
Because of their spaceeeee isss different
We are using the General gas equation P x V/K = P x V/K
1. P = 1atm V=500ml so PxV= 500 at 6.5km P = 0.5atm V = ? so P xV = 0.5 x V
(We don't have to worry about temperature!) 500 = 0.5 x V so V = 1000ml
2. NO CHANGE in pressure here so we have V/K V=2.75 K = 20 + 273=293 so V/K= 2.75/293
Next set V = 2.46 K = ? so V/K = 2.46/K then 2.75/293= 2.46/K so K=(293/2.75)x2.46
=262 K
Convert back to Celsius 262 - 273 = -11 C
It's raining so I have to rescue the laundry!
Laundry rescued!
3.Now we have to use all three variables. I am using 273K and 100kPa for STP.
P = 100 V = 700 K = 273 These are altered P - unknown, V = 200 K = 273+30=303
!00 x 700/273 = 256.4 this is equal to P x 200/303 = P x 0.66
so P = 256.4/0.66 = 388.48kPa
Answer:
10.8 g
Explanation:
<em>A chemist adds 480.0 mL of a 0.169 mol/L aluminum chloride solution to a reaction flask. Calculate the mass in grams of aluminum chloride the chemist has added to the flask. Round your answer to 3 significant digits.</em>
Step 1: Given data
- Volume of the solution: 480.0 mL
- Concentration of the aluminum chloride solution: 0.169 mol/L
Step 2: Calculate the moles of aluminum chloride in the solution
We will multiply the volume of the solution by the molarity.
0.4800 L × 0.169 mol/L = 0.0811 mol
Step 3: Calculate the mass corresponding to 0.0811 moles of AlCl₃
The molar mass of AlCl₃ is 133.34 g/mol.
0.0811 mol × 133.34 g/mol = 10.8 g
