The electric field E of a charge is defined as E=F/Q where F is the Coulomb force and Q is the test charge.
E=(1/Q)*k*(q*Q)/r², where k=9*10^9 N*m²/C², q is the point charge, Q is the test charge and r is the distance between the charges.
So E=(k*q)/r²
When we input the numbers we get that electric field E of a point chage q is:
E=(9*10^9)*(5.4*10^-8)/0.2²=486/0.04=12150 N/C.
This is roughly E=12000 N/C =1.2*10^4 N/C
The correct answer is B.
The part of the ignition system that amplifies the electric
voltage is the coil as it is described to be something that is joined in a
shape of a spiral or rings in a specific machine or vehicle, amplifying
electricity.
No answer is possible, because you denied us the opportunity
to use any of the information in the picture.
Answer:
= 8.33 Watt
Explanation:
where,
p = resistivity
l = length
A = cross section area
Given that ,
p = resistivity = 6.0 × 10–8 Ω
l = 2m
A = cross section area = 2.0 mm × 2.0 mm = 4 x 10^-6 m^2
A = 2 x 2 mm^2 = 4 x 10^-6 m^2
p = 6 x 10^-8 ohm metre,
V = 0.5 V
Let R be the resistance of the rod
R = 3 × 10⁻²Ω
Heat generated = V^2 / R
= (0.5)^2 / (3 x 10^-2)
= 8.33 Watt
