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3 years ago

6

Mia needs to separate 450 pens into 18 packs.each pack will have the same number of pens. How many pens should be put in each pa

ck

2 answers:

nordsb [41]3 years ago

8 0

All you would need to do is divide 450 by 18. This equals 25. So, 25 pens should be put into each pack.

I hope this helps you! Comment if you have any questions or need help with anything else. :)

sertanlavr [38]3 years ago

6 0

Do 450 divided by 18, which equals 25

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Solving Inequalities Using Addition or Sub

wariber [46]

I believe it’s x < 9

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3 years ago

. If a basketball player made 72 of 85 free throws, how many free throws could she expect to make in 200 attempts?

katrin2010 [14]

Answer:

169 of the 200 free throws

Step-by-step explanation:

You would expect her to make at least 169 of the 200 free throws

4 0

3 years ago

Plz help me!!!!!i need to get this correct plz help!!!

____ [38]

Answer:

Yes

Step-by-step explanation:

Yes they are because if you divide 18 by 3 you get six and if you divide 15 by 3 you get 5, so it simplifies to 6:3 which is the same as the ratio for rings

3 0

3 years ago

The admission fee is $1.50 for children and $4.00 for adults. If 2700 people enter and $7800 is collected how many children and

mash [69]

Number of children attended is 1200 and number of adults attended is 1500

<h3><u>Solution:</u></h3>

Given that,

Admission fee for each children = $ 1.50

Admission fee for each adult = $ 4.00

Let "c" be the number of children attended

Let "a" be the number of adults attended

Given that 2700 people enter and $7800 is collected

Number of children attended + number of adults attended = 2700

c + a = 2700 -------- eqn 1

Also given that $7800 is collected

Number of children attended x Admission fee for each children + number of adults attended x Admission fee for each adult = 7800

$c \times 1.50 + a \times 4 = 7800$

1.5c + 4a = 7800 -------- eqn 2

Let us solve eqn 1 and eqn 2 to find values of "a" and "c"

From eqn1,

a = 2700 - c ----- eqn 3

Substitute eqn 3 in eqn 2

1.5c + 4(2700 - c) = 7800

1.5c + 10800 - 4c = 7800

-2.5c = -3000

c = 1200

Therefore from eqn 3,

a = 2700 - 1200

a = 1500

Therefore number of children attended = c = 1200

number of adults attended = a = 1500

3 0

3 years ago

Is there any video related to this or can you explain how to do it

uranmaximum [27]

Angles ECD and CEF add to 180

40+140 = 180

So that means we have EF parallel to CD (due to the same side interior angle theorem)

--------------

Angles BCE and ECD combine to 30+40 = 70, which is congruent to angle ABC = 70 as well.

In other words, this shows angle ABC = angle BCD. Both of these angles are alternate interior angles. Since they're congruent, they lead to AB being parallel to CD.

--------------

So far we have

AB || CD

CD || EF

Using the transitive property, we can then link the two statements to say AB || EF. Think of a chain where CD is the common link. We go from AB to CD, then from CD to EF. So we can just take a single path from AB to EF.

It's like saying "P --> Q and Q --> R, therefore P --> R"

4 0

3 years ago