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Jlenok [28]
3 years ago
5

What is the domain of the function f(x) 2/5 startroot x = ? all real numbers all real numbers less than 0 all real number less t

han or equal to 0 all real numbers greater than or equal to 0
Mathematics
2 answers:
victus00 [196]3 years ago
7 0

Answer:

D. all real numbers greater than or equal to 0

Step-by-step explanation:

Edge 2020

lina2011 [118]3 years ago
5 0

Answer:

\boxed{\sf all \ real \ numbers \ greater \ than \ or \ equal \ to \ 0}

Step-by-step explanation:

The domain of a function is all possible values for x.

\sf f(x)=\frac{2}{5} \sqrt{x}

There are restrictions on x.

The square root of a number can be undefined if that number is less than 0.

The value of x is all real numbers greater than or equal to 0.

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The three inside angles (A,B and C) of a right-angled triangle are in the ratio 7:18:11. Th smallest angle is 35. Work out angle
lions [1.4K]

Answer:

<A = 35degrees

<B =90degrees

<C = 55degrees

Step-by-step explanation:

Given the ratios of a triangle as 7:18:11

Total ratio = 7+18+11

Total ratio = 36

Since the smallest angle is 35degrees, hence <A = 35degrees

Get angle B;

<B = 18/36 * 180 (sum of angle in a triangle is 180degrees)

<B = 1/2 * 180

<B = 90degrees

Get angle C;

<C = 11/36 * 180

<C = 11 * 5

<C = 55degrees

Hence the value of A, B and C are 35, 90 and 55 degrees repectively

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3 years ago
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Answer:

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