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Jlenok [28]
3 years ago
5

What is the domain of the function f(x) 2/5 startroot x = ? all real numbers all real numbers less than 0 all real number less t

han or equal to 0 all real numbers greater than or equal to 0
Mathematics
2 answers:
victus00 [196]3 years ago
7 0

Answer:

D. all real numbers greater than or equal to 0

Step-by-step explanation:

Edge 2020

lina2011 [118]3 years ago
5 0

Answer:

\boxed{\sf all \ real \ numbers \ greater \ than \ or \ equal \ to \ 0}

Step-by-step explanation:

The domain of a function is all possible values for x.

\sf f(x)=\frac{2}{5} \sqrt{x}

There are restrictions on x.

The square root of a number can be undefined if that number is less than 0.

The value of x is all real numbers greater than or equal to 0.

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Directions: Find the complemen
andre [41]

Given:

The angles are:

Example 54^\circ

1. 63^\circ

2. 87^\circ

3. 45^\circ

4. 72^\circ

5. 5^\circ

To find:

The complimentary angle of the given angles.

Solution:

If two angles are complimentary, then their sum is 90 degrees.

Example: Let x be the complimentary angle of 54^\circ, then

x+54^\circ=90^\circ

x=90^\circ -54^\circ

x=36^\circ

Similarly,

1. The complimentary angle of 63^\circ is:

90^\circ -63^\circ=27^\circ

2. The complimentary angle of 87^\circ is:

90^\circ -87^\circ=3^\circ

3. The complimentary angle of 45^\circ is:

90^\circ -45^\circ=45^\circ

4. The complimentary angle of 72^\circ is:

90^\circ -72^\circ=18^\circ

5. The complimentary angle of 5^\circ is:

90^\circ -5^\circ=85^\circ

Therefore, the complimentary angles of 54^\circ, 63^\circ, 87^\circ, 45^\circ, 72^\circ, 5^\circ are 36^\circ, 27^\circ, 3^\circ, 45^\circ, 18^\circ, 85^\circ respectively.

6 0
3 years ago
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