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The rate of disappearance of HBr in the gas phase reaction2HBr(g) → H2(g) + Br2(g)is 0.301 M s-1 at 150°C. The rate of appearanc

jok3333 [9.3K]

Answer: 0.151

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

$2HBr(g)\rightarrow H_2(g)+Br_2(g$

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

$Rate=-\frac{1d[HBr]}{2dt}=+\frac{1d[H_2]}{2dt}=+\frac{1d[Br_2]}{dt}$

Given: $-\frac{d[HBr]}{dt}]=0.301$

Putting in the values we get:

$\frac{0.301}{2}=+\frac{1d[Br_2]}{dt}$

$+\frac{1d[Br_2]}{dt}=0.151$

Thus the rate of appearance of $Br_2$ is 0.151

8 0

3 years ago

Match each item with the correct statement below.

adell [148]

1. Formula

2. Compound

3. Properties

4. Solute

5. Mass

6. Matter

7. Alloy

8. aqueous solution

9. quantitative

5 0

4 years ago

Read 2 more answers

Please help me with these two questions

ANEK [815]

What is the question?

8 0

3 years ago

When a person in the hospital is given fluids intravenously, the fluid is typically a saline (salt) solution with about the same

Sati [7]

Answer:

Swelling of the red blood cells occurs.

Explanation:

Distilled water makes the blood hypotonic ,. that is a less concentrated solution, to the body tissues including the red blood cells.
Therefore the water will enter the red blood cells and may cause them to lyse or swell.
Additionally , water will enter the tissue spaces and cause sweling.
But in the case of a hypertonic solution , ( a salt or saline solution ) , This swelling does not happen because the concentration of the saline will be equal or more than the blood. 
Thus the water will flow only from the blood to the solution. This will not cause swelling.
But too much of salt is also not recommended.

5 0

3 years ago

Find the vapor pressure of a water solution in which the

zheka24 [161]

Answer:

The vapor pressure in solution is 0,0051 atm

Explanation:

This is the formula for vapor pressure lowering, the colligative property.

P vapor = Pressure sv pure . Xsv

Where Xsv is data.

Xsv means Molar fraction (moles solvent/total n° moles)

Vapor pressure of water, pure is 17.5 mmHg

P vapor = 0,0313 atm . 0163

P vapor in solution = 0,0051 atm

Molar fraction does not have units

A solution will have less vapor pressure than that observed in the pure solvent.

5 0

3 years ago