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rusak2 [61]
2 years ago
12

Help me clarify please!

Chemistry
1 answer:
zaharov [31]2 years ago
7 0

Answer:

Round to the number of significant figures in the original question. However, if you're going to proceed with further calculations using this mass, it's best not to round, as rounding will cause your answer to be less precise.

Explanation:

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If a shell can hold a maximum of 32 electrons, what is the value of n?
olga2289 [7]
<span>Begin by classifying which energy level, and indirectly principal quantum number, n, resembles to the N shell. no. of orbitals =n2 In your case, the fourth energy level will contain n=4⇒no. of orbitals= 4^2=16 The number of subshells is given by the principal quantum number. no. of subshells=n In your case, the fourth energy level will have no. of subshells = 4 this is the answer to check: the fourth energy shell will can hold a thoroughgoing of no. of electrons=2⋅42=32 e−</span>
4 0
3 years ago
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Calculate the change in entropy if Br2(l) is converted to Br2(g).
Alik [6]

Ans: The entropy change for the given reaction is 93.3 J/K

Given reaction:

Br2(l) → Br2(g)

ΔS = ∑n(products)S⁰(products) - ∑n(reactants)S⁰(reactants)

     = 1 mole* S°(Br2(g)) - 1 mole*S°(Br2(l))

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5 0
3 years ago
Two liquids, 1 and 2, are in equilibrium in a u-tube that is open at both ends. the liquids do not mix, and liquid 1 rests on to
Artyom0805 [142]
I believe the density p1 is greater than the density p2 .
Since the liquid are at equilibrium in the the open U-tube, the pressure at which the liquids meet should be the same. That is at the position where they are in contact, the pressure that liquid 1 exerts at that point is the same as the pressure exerted by liquid 2 at the point. 
6 0
3 years ago
Match each transition metal ion with its condensed ground-state electron configuration. A [Ar]3d2 B [Ar]4s23d3 C [Kr]4d10 D [Xe]
madreJ [45]

Answer:

Mn^{2+} : - F . [Ar]3d^{5}

Hg^{2+} : - G. [Xe]4f^{14}5d^{10}

La^{3+} : - D. [Xe]

Fe^{3+} : - F. [Ar]3d^{5}

Ag^{+} : - C. [Kr]4d^{10}

Co^{3+} : - E. [Ar]3d^{6}

Explanation:

The electronic configuration of the element Mn is:-

[Ar]3d^{5}4s^2

For, Mn^{2+}, 2 electrons are lost, thus the configuration is:-

[Ar]3d^{5}

The electronic configuration of the element Hg is:-

[Xe]4f^{14}5d^{10}6s^2

For, Hg^{2+}, 2 electrons are lost, thus the configuration is:-

[Xe]4f^{14}5d^{10}

The electronic configuration of the element La is:-

[Xe]5d^{1}6s^2

For, La^{3+}, 3 electrons are lost, thus the configuration is:-

[Xe]

The electronic configuration of the element Fe is:-

[Ar]3d^{6}4s^2

For, Fe^{3+}, 3 electrons are lost, thus the configuration is:-

[Ar]3d^{5}

The electronic configuration of the element Ag is:-

[Kr]4d^{10}5s^1

For, Ag^{+}, 1 electron is lost, thus the configuration is:-

[Kr]4d^{10}

The electronic configuration of the element Co is:-

[Ar]3d^{7}4s^2

For, Co^{3+}, 3 electrons are lost, thus the configuration is:-

[Ar]3d^{6}

7 0
3 years ago
Can beans grow inside water
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No, They need something to hold on to, such as dirt
8 0
3 years ago
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